All categories

3 years ago

Simplify the following expression, if possible. (xyz)6

Mathematics

2 answers:

saw5 [17]3 years ago

8 0

Answer:

Answer is below

Step-by-step explanation:

The simplified expression would be 6xyz because you distribute the 6 to the (xyz).

If this answer is correct, please make me Brainliest!

ikadub [295]3 years ago

7 0

6xyz because you multiply 6 by each term

You might be interested in

Which ordered pairs lie on the graph of the exponential function f(x)=2(x+4)−8f(x)=2(x+4)−8 ?

sergejj [24]

Simplify the equation
f(x) = 2x + 8 - 8
f(x) = 2x

Now substitute the x values
f(24) = 2(24) = 48
f(8) = 2(8) = 16
f(2) = 2(2) = 4
f(-2) = 2(-2) = -4

The correct answer is 4. (-2,-4)

6 0

3 years ago

Read 2 more answers

Combine the like terms to make a simpler expression: <br> −3k−(−8)+2

Alex777 [14]

The answer to this question is: -3k+10

5 0

3 years ago

The equation shows the relationship between x and y:

wlad13 [49]

Answer: -7

Step-by-step explanation:

The equation is in slope-intercept form (y=mx+b), where m is the slope and b is the y-intercept

Therefore, the m value is -7 and it is the slope

4 0

2 years ago

What are the zeros of this function?

blondinia [14]

Answer:

Try D

Step-by-step explanation:

8 0

3 years ago

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

4 years ago