3 years ago

The sum of 5 consecutive integers is 265

1 answer:

5 0

Suppose the first one is n, the second is then n+1, the third is n+2, ....
n+(n+1)+(n+2)+(n+3)+(n+4)=265
5n+10=265
5n=255
n=51
so the 5 consecutive integers are: 51,52,53,54,55

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