5.5 × 2= 11
11 is the length.
perimeter= 11+11+5.5+5.5
The perimeter is 33 units.
We can't find the hundredth for you, but the nearest hundred is $95,500.
11
(9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99)
Those numbers divisible by 9 are the multiple of 9; thus need to know how many multiples of 9 there are between 1 and 100:
100 ÷ 9 = 11 r 1 ÷ last multiple of 9 is 11 × 9 (= 99)
→ There are 11 - 1 + 1 = 11 numbers between 1 and 100 which are divisible by 9.
(They are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.)
Answer:
1/2
Step-by-step explanation:
Replace x and y in the equation with what they tell you x and y equal.
2(14) / 13 - 9(1/3)
Now simplify:
2 x 14 = 28
9 x 1/3 = 3
You now have:
28/13-3
Simplify again to het 28/10 this can be reduced to 14/5
