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3 years ago

What is the exact value that is 48% of 1165

1 answer:

5 0

We know that the percentage amount of any number can be found by first converting the the given percentage to a fraction and then multiplying it by the given number. Thus, in our case, the exact value, that is 48% of 1165 can be calculated as follows:

We know that $48\%=\frac{48}{100}=0.48$

Therefore, 48% of 1165 can be re-written as: $0.48\times 1165$

This can be calculated as [tex]0.48\times 1165=559.2[/tex

Therefore The exact value that is 48% of 1165 is 559.2

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Show all steps necessary to verify the trigonometric identity:

vekshin1

Answer:

1+tan2x

Tan2x

= sec²x = Sec²x = cosec²x

Tan²x ( Sec²x/cosec²x)

Step-by-step explanation:

4 0

2 years ago

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Please solve this for me thank you!

melamori03 [73]

Answer:

620.14

Step-by-step explanation:

Original Equation:

$\frac{4y}{1.025^4}+y-2y(1.05)^2=1500$

Calculate exponents

$\frac{4y}{1.103812890625}+y-2y(1.1025)=1500\\$

Simplify:

$3.6238025791990193084270042653997y + y - 2.205y = 1500$

Add like terms

$2.4188025791990193084270042653997y \approx 1500$

Divide both sides by 7.012

$y\approx 213.91$ $y\approx620.14$

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2 years ago

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Solving the linear equations variable on one side

Brums [2.3K]

The pick up fee is $2.50.

After each mile, $1.95 is added.

That is, after the first mile, we have;

$\begin{gathered} \text{Fe}e=\text{ 2.50 + 1.95(1)} \\ \text{After the second mile, we have;} \\ Fee=\text{ 2.50+1.95(2)} \end{gathered}$

Isaac total charge = $27.46;

Generally, let the number of miles driven by the taxi be x, then we have;

$1.95x+2.50=27.46$

Solving for the number of miles Isaac travelled, we have;

$\begin{gathered} 1.95x=27.46-2.50 \\ 1.95x=24.96 \\ x=\frac{24.96}{1.95} \\ x=12.8\text{miles} \end{gathered}$

CORRECT OPTION:

$1.95x+2.50=27.46;\text{ Isaac traveled 12.8 miles.}$

4 0

1 year ago

Among 35 students in a class, 20 of them earned A's on the midterm exam, 13 earned A's on the nal exam, and 12 did not earn A's

enyata [817]

Answer:

The correct answer is " $\frac{2}{7}$ ".

Step-by-step explanation:

According to the question,

Number of students,

= 35

A ! mid term A,

$n(A) = 20$

B : final A,

$n(B) = 13$

Didn't start,

$n(A^c \cap B^c) = 12$

Now,

⇒ $n(A \cup B)=35-12$

$=23$

then,

⇒ $n(A \cup B)=20+13-23$

$=10$

hence,

The probability will be:

⇒ $P(A \cap B)=\frac{10}{35}$

⇒ $=\frac{2}{7}$

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2 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$