A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is
A. 0.037773 to 0.202227
B. 3.7773% to 20.2227%
C. 59.98786% to 61.01214%
D. 51.7773% to 68.2227%
E. 10.988% to 13.012%
Answer: E. 10.988% to 13.012%
Step-by-step explanation:
Given;
Mean x= 12%
Standard deviation r = 4%
Number of samples tested n = 60
Confidence interval is 95%
Z' = t(0.025)= 1.96
Confidence interval = x +/- Z'(r/√n)
= 12% +/- 1.96(4%/√60)
= 12% +/- 0.01214%
Confidence interval= (10.988% to 13.012%)
Answer:
4
Step-by-step explanation:
Nothing else rlly works besides 1,2,4 soo
Kono Dio Da!!!
Using proportions, considering the total number of students, it is found that 216 boys to linking their school lunch.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In this problem, 400 - 152 = 248 boys were surveyed. 32 said they liked the school lunch and 248 - 32 = 216 said no liking their school lunch.
More can be learned about proportions at brainly.com/question/14398287
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X would be 0 while Y would be 4
3x+y=4
-(2x+y=4)
----------------
x=0
Plug in x to any of those two equations in their original form
3(0)+y=4
0 + y = 4
y = 4
Answer:
2,850
Step-by-step explanation:
4.25 x 9 = 38.25
4.25 x 13 = 55.25
4.25 x 12 = 51
13.70 x 92 = 1260.4
3.28 x 130 = 426.4
8.06 x 126 = 1015.56
all totals would equal 2,846.86, which to the nearest would be $2,850
