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3 years ago

I need help bad and fast

Mathematics

2 answers:

Sophie [7]3 years ago

7 0

Answer:

Step-by-step explanation:

CD is the answer because the graph becomes a flat line when a body is at rest

ivann1987 [24]3 years ago

3 0

Answer: E) CD

Step-by-step explanation:

A segment with a slope of 0 on this graph represents a time where no distance is made, or a break. The only segment with a slope of 0(where distance does not increase) is segment CD.

Hope it helps <3

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If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid

Artist 52 [7]

Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

$\bf \textit{volume of a rectangular prism}\\\\
V=lwh\quad 
\begin{cases}
l = length\\
w=width\\
h=height\\
-----\\
w=l=x
\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\
-------------------------------\\\\
\textit{surface area}\\\\
S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h
\\\\\\
\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\
-------------------------------\\\\
V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3$

so.. that'd be the V(x) for such box, now, where is the maximum point at?

$\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2
\\\\\\
\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100
\\\\\\
x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}$

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.

so, the volume will then be at $\bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3$

6 0

3 years ago

Ben is buying pens and pencils from the store. Pens come in packages

Alinara [238K]

The smallest number of pens he can buy is 4 packages

7 0

3 years ago

Find d:

BlackZzzverrR [31]

Answer:

D = 51, other = 30

Step-by-step explanation:

d = | 5 1 |

|-1 10|

D = (5 x 10) - ( 1 x -1) = 50 + 1 = 51

| 2 4|

|-3 9|

(2 x 9) - (4 x -3) = 18 + 12 = 30

6 0

3 years ago

A recent study claims that business travelers spend an average of $39 per day for meals. A sample of 15 business travelers found

4vir4ik [10]

Answer:

The test statistic value 't' = 3.074

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 15

mean of the Population 'μ' = $39

mean of the sample x⁻ = $42

standard deviation of the sample 's' = $3.78

Degrees of freedom ν = n-1 = 15-1 =14

$t_{\frac{\alpha }{2} } = 1.769$

Null hypothesis : There is no significance difference between the means

H₀ : x⁻ = 'μ'

Alternative hypothesis : There is significance difference between the means

H₀ : x⁻ ≠ 'μ'

Test statistic

$t = \frac{x^{-} -mean}{\frac{s}{\sqrt{n} } }$

$t = \frac{42 -39}{\frac{3.78}{\sqrt{15} } }$

t = 3.074

The test value of t-statistic t = 3.074

The calculated value t = 3.074 > 1.769 at 0.05 level of significance

null hypothesis is rejected

Alternative hypothesis is accepted

Final answer:-

There is significance difference between the means

4 0

3 years ago

Eve is organizing a race to raise money for a local children's hospital. She makes $20 for each 5K participant and $45 for each

Nastasia [14]

Answer: $20x +45y=9500$ is the linear equation.

yes, it is possible.

Step-by-step explanation:

given data:

we were told that she would make $20 for each 5K participant and $45 for each 10K participant.

cost of each 5k participant = $20

cost of each 10k participant = $45.

her target = $9500

solution:

let y represent the 10k

let x represent the 5k participant

the linear equation for this scenarios is

$20x +45y=9500$

(b.) possibility of having 220 participant in the 5k race.

$\\20(220) +45y=9500\\4400 + 45y = 9500\\45y = 9500- 4400\\45y = 5100\\y = \frac{5100}{45} \\y = 113$

7 0

2 years ago

Read 2 more answers