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MArishka [77]
4 years ago
11

Liam is setting up folding chairs for a meeting. If he arranges the chairs in 9 rows of the same length, he has 11 chairs left o

ver. If he arranges the chairs in 7 rows of that same length, he has 21 left over. How many chairs does Liam have?
Mathematics
2 answers:
prisoha [69]4 years ago
4 0

Answer:

48 :)

Step-by-step explanation:

FREE POINTS ON MY PAGE

uranmaximum [27]4 years ago
3 0
40 SHOULD BE THE RIGHT ANSWERRRR
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Find the minimum or maximum value of the function g(x)= -(x-2)^2-3
Nady [450]
Neato

assuming you mean
g(x)=-1(x-2)^2-3
remember
in form
f(x)=a(x-h)^2+k
a is leading coficient
(h,k) is vertex
k will be the minimum or max value of the function
if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max

given
g(x)=-1(x-2)^2-3
a is negative
the parabola opens down and k is the max value
it is -3
the max value is -3, which occors at x=2
g(2)=-3 is max
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4 years ago
What is the value of -<br> -X2 - 4x – 11 if x = -3?
qaws [65]
The answer to this question is -8
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3 years ago
GIVING BRIANLIEST PLS HELP
Ivenika [448]

Step-by-step explanation:

a) Line AB ll DC

b) Line GH acts as a transversal.

c) <10 ; <12 , <9 ; <11

d) <8 = 180° - 120° = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<6 = <u>120</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<5 = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<4 = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<3 = <u>120</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<2 = <u>120</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<1 = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

5 0
3 years ago
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When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve
Akimi4 [234]

Answer:

5\frac{3}{10}  cans extra food is needed to feed the second cat.

Step-by-step explanation:

Given:

When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve a total of 11/2 cans each day.

Now, to find the extra food is needed to feed the second cat.

Food needed for one cat = \frac{1}{5}\ of\ can.

Food needed for both one and second cat needed = \frac{11}{2}\ =5\frac{1}{2}\ cans.

Now, extra food needed to feed the second cat:

<u><em>Food needed for both one and second cat needed - food needed for one cat.</em></u>

<u><em /></u>\frac{11}{2} -\frac{1}{5}\\\\=\frac{55-2}{10} \\\\=\frac{53}{10}<u><em /></u>

<u><em /></u>=5\frac{3}{10}\ cans.<u><em /></u>

Therefore, 5\frac{3}{10}\ cans extra food is needed to feed the second cat.

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omeli [17]

Answer:

You didn't send anything

Step-by-step explanation:

6 0
3 years ago
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