Answer:
4/1. ( not so sure tho)
Step-by-step explanation:
=[(6/6)×(6/6)] + [(5/6)×(6/6)] + [(6/6)×(5/6)]
=(36/36) + (30/36) + (30/36)
=(taking LCM) 96/36
=4/1.
hope this helps
Answer:
x²-12x+36
Step-by-step explanation:
Answer:
dependent events since P(A and B) is not equal to P(A) * P(B)
Step-by-step explanation:
According to the Question,
- Given, The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballgame (event B) the same day is 0.61. The probability that Kate and Jane both go to the ballgame on Monday is 0.52.
Thus, The events A, B and A∩B are:
A - Jane will go to a ballgame on Monday;
B - Kate will go to a ballgame on Monday;
A∩B - Kate and Jane both go to the ballgame on Monday.
- P(A)=0.73, P(B)=0.61, P(A∩B)=0.52.
- Pr(A)⋅Pr(B) = 0.73⋅0.61 = 0.4453 ≠ 0.52
So, events A and B are dependent events since P(A and B) is not equal to P(A) * P(B)
