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Akimi4 [234]
3 years ago
13

A doctor wants to estimate the mean HDL cholesterol of all​ 20- to​ 29-year-old females. How many subjects are needed to estimat

e the mean HDL cholesterol within 2 points with 99 % confidence assuming s equals 15.6 based on earlier​ studies? Suppose the doctor would be content with 95 % confidence. How does the decrease in confidence affect the sample size​ required?
Mathematics
1 answer:
REY [17]3 years ago
8 0

(a) 404 subjects are needed to estimate the mean HDL cholesterol within 2 points with 99% confidence.

(b) When the confidence level decreases to 95%, the number of subjects decreases from 404 to 234.

<u>Explanation:</u>

Given:

σ = 15.6

Let the number of subjects be n

(a)

When the confidence level is 99%, then z = 2.576

E = 2

We know:

n = [\frac{z X s}{E}]^2

On substituting the value, we get:

n = [\frac{2.576 X 15.6}{2} ]^2\\\\n = 403.7

Thus, 404 subjects are needed to estimate the mean HDL cholesterol within 2 points with 99% confidence.

(b)

When the confidence level is 95%, then z = 1.96

E = 2

We know:

n = [\frac{z X s}{E}]^2

On substituting the value, we get:

n = [\frac{1.96 X 15.6}{2} ]^2\\\\n = 233.7

n = 234

Thus, when the confidence level decreases to 95%, the number of subjects decreases from 404 to 234.

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2 years ago
What is the speed of a train that travels 52 kilometers in 3 hours?
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17 km/h

Step-by-step explanation:

52:3=17.3≈17   km/hour

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Becky has 8 more marbles than Kim. Together they have 76 marbles. Find the number of marbles that Kim has​
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Step-by-step explanation:

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3 years ago
EU (European Union) countries report that 46% of their labor force is female. The United Nations wants to determine if the perce
miss Akunina [59]

Answer:

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

Step-by-step explanation:

1) Data given and notation  

n=500 represent the random sample taken    

X represent the number of females in the U.S. labor force

\hat p=0.46 estimated proportion of females in the U.S. labor force

\alpha=0.05 represent the significance level (no given, but is assumed)    

z would represent the statistic    

p= population proportion of females in the U.S. labor force

2) Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.46 - 1.96 \sqrt{\frac{0.46(1-0.46)}{500}}=0.416

0.46 + 2.58 \sqrt{\frac{0.46(1-0.46)}{500}}=0.504

On this case the calculated interval is not the given , but let's assume that the confidence interval is given by the statment: "United States Department of Labor find that 95% confidence interval for the proportion of females in the U.S. labor force is .357 to .443."

3) Correct interpretation

a. The margin of error for the true percentage of females in the U.S. labor force is between 35.7% and 44.3%.

False the confidence interval not conclude about the margin of error conclude about the true proportion.

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

True, the statement report the confidence level and the limits for the margin of error.

c. The percentage of females in the U.S. labro force is between 35.7% and 44.3%.

False, The statement is not correct because not reports the confidence level.

d. All sample of size 500 will yield a percentage of females in the U.S. labor force that falls within 35.7% and 44.3%

False the confidence interval is for the population proportion not just for the samples of size 500

e. None of these.

False, we have an option that is true.

8 0
3 years ago
On Monday a team of street sweepers cleaned 2/5 of a city block. Tuesday, the team cleaned 4/5 as
otez555 [7]

Answer:

1 and 1/5

Step-by-step explanation:

\frac{2}{5} + \frac{4}{5} = \frac{6}{5} or 1 \frac {1}{5}

8 0
3 years ago
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