Ask question

Ask question

All categories

3 years ago

10

How are a function and its inverse related?

1 answer:

marta [7]3 years ago

7 0

Answer:

They reverse each other.

Step-by-step explanation:

A function and an inverse of a function undo what the other does. For example, a function gives an ordered pair of (5,0). Therefore, the inverse would give an ordered pair (0,5).

You might be interested in

1: Ken earned $176 from his part-time job this summer. He spent 25% of his money on games. He is going to donate 14 of the rema

tatiyna

The charity will receive $ 11

<h3><u>Solution:</u></h3>

Ken earned $176 from his part-time job this summer

Amount earned = $ 176

He spent 25% of his money on games

Therefore,

Money spent on games = 176 - 25 % of 176

$\text{Money spent on games } = 176 - \frac{25}{100} \times 176\\\\\text{Money spent on games } = 176 - 0.25 \times 176\\\\\text{Money spent on games } = 176 - 44\\\\\text{Money spent on games } = 132$

He is going to donate 1/4 of the remaining money to charity

Reamining amount = 176 - 132 = 44

Therefore,

$Money\ given\ to\ charity = \frac{1}{4} \times 44 = 11$

Thus he gave $ 11 to charity

8 0

3 years ago

Danielle has taken five math tests so far this year. The tests are out of twenty points, and she has gotten the following scores

Doss [256]

Answer:

Danielle score must be 18

8 0

2 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

3 years ago

Can someone solve this question

pogonyaev

(g/f)(x)= g(x)/f(x) =

= (x² - 6) /(3x +1)

3x+1≠0

3x≠-1

x≠ - 1/3

(g/f)(x)= (x² - 6) /(3x +1), when x≠ - 1/3

Answer: A.

6 0

3 years ago

I really need help with this any1?

maxonik [38]

Answer:

2x-4 = -8

Step-by-step explanation:

5 x -22= -110

4 0

2 years ago