All categories

3 years ago

Please explain how to do it

Mathematics

1 answer:

eimsori [14]3 years ago

5 0

The 4 tells you how much 0 you have so you have 4 zeros your number will be10000 and you multiple 10,000 Times 20 hopes I helped

You might be interested in

Write an equation of the line that is perpendicular to the line y = 1 2 x + 8 that passes through the point (4,6)

Katen [24]

Answer:

$\large\boxed{y=-2x+14}$

Step-by-step explanation:

$\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=\dfrac{1}{2}x+8\to m_1=\dfrac{1}{2}.\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{2}}=-2.\\\\\text{The equation of the searched line:}\ y=-2x+b.\\\\\text{The line passes through }(4,\ 6).$

$\text{Put thecoordinates of the point to the equation.}\ x=4,\ y=6:$

$6=-2(4)+b\\\\6=-8+b\qquad\text{add 8 to both sides}\\\\b=14$

6 0

3 years ago

Read 2 more answers

Plz!!!!! help me what do i put in the box help me!!!!

Gnesinka [82]

Answer:

Step-by-step explanation:

Volume = area × height

= 210 × 7

= 1470cubic inch

7 0

3 years ago

Assume y≠60 which expression is equivalent to (7sqrtx2)/(5sqrty3)

Drupady [299]

Answer:

The equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

Step-by-step explanation:

Given the expression

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

Let us solve the expression step by step to get the equivalent

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

$\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=x^{2\cdot \frac{1}{7}}$

$=x^{\frac{2}{7}}$

also

$\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=y^{3\cdot \frac{1}{5}}$

$=y^{\frac{3}{5}}$

so the expression becomes

$\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$ ∵ $\:\frac{1}{y^{\frac{3}{5}}}=y^{-\frac{3}{5}}$

Thus, the equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

5 0

3 years ago

Carlos runs 7 miles in 57 3/4 mins. how fast did he run each mile?

san4es73 [151]

To find how much minutes Carlos runs each mile, you must first multiply 57.75 by 1 which is 57.75 because 57 3/4 and 57.75 is the same thing. Next, you must divide 57.75 by 7. Therefore, Carlos runs 8.25 minutes a mile.

3 0

3 years ago

Which expression shows 7 more than the product of 8 times 9?

dsp73

Answer:

Step-by-step explanation:

7 more than the product of 8 times 9

product of 8 times 9 = 8 × 9 = 72

7 more than the product of 8 times 9 = 72 + 7 = 79

Hope this helps

plz mark as brainliest!!!!!!!!!!

4 0

4 years ago