Question

PLEASE HELP 30 POINTS!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Since you know the value of "x", you can plug in the value for "x" in the equation.

[When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.]

For example:

$x^{-2}$  or  $\frac{x^{-2}}{1} =\frac{1}{x^2}$

$\frac{1}{y^{-3}} =\frac{y^3}{1}$  or  y³

x = -2

f(x) = 9x + 7

f(-2) = 9(-2) + 7 = -18 + 7 = -11

$g(x)=5^x$

$g(-2)=5^{-2}=\frac{1}{5^2}=\frac{1}{25}$   (idk if you should have it as a decimal or a fraction)

x = -1

f(x) = 9x + 7

f(-1) = 9(-1) + 7 = -9 + 7 = -2

$g(x)=5^x$

$g(-1)=5^{-1}=\frac{1}{5}$

x = 0

f(x) = 9x + 7

f(0) = 9(0) + 7 = 7

$g(x)=5^x$

$g(0)=5^0=1$

x = 1

f(x) = 9x + 7

f(1) = 9(1) + 7 = 9 + 7 = 16

$g(x)=5^x$

$g(1)=5^1=5$

x = 2

f(x) = 9x + 7

f(2) = 9(2) + 7 = 18 + 7 = 25

$g(x)=5^x$

$g(2)=5^2=25$

You need to determine the solution of f(x) = g(x)

Since you know f(x) = 9x + 7 and $g(x)=5^x$, you can plug in (9x + 7) for f(x), and ($5^x$) into g(x)

f(x) = g(x)

$9x+7=5^x$   You can plug in each value of x into the equation

Your answer is x = 2 because when you plug in 2 for x in the equation, you get 25 = 25