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Evaluate:
when 
First, add x's:

Now, plug in the value of x (3)

Multiply:`
(Answer)
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<em>Answered by</em>
<em>~</em>Silent~
Answer:
The expected value of profit is -0.5125. This is expected loss as value is negative.
Step-by-step explanation:
We are given the following in the question:
P(winning) = 0.075
Thus,
P(Loosing) =

If we win we gain a profit of $5.50 and if we loose the lottery, we loose $1.
Thus, we can form the probability distribution in the following manner:
Event: Winning Loosing
Profit(x): +5.50 -1
P(x): 0.075 0.925
We have to calculate the expected value of the profit.

Thus, the expected value of profit is -0.5125. This is expected loss as value is negative.
Answer:
From least to greatest: -2, 2/3
Step-by-step explanation:
Set each factor equal to 0 and solve
2x + 4 =0
2x = -4
x = -2
3x - 2 = 0
3x = 2
x = 2/3
This question has extraneous info to trick you.
f(x) = g(x)h(x) ⇒ f'(x) = g'(x)h'(x) . Letting x = 10, we get f'(10) = g'(10)h'(10). then just plug in the values provided. g(10) and h(10) are there to throw you off, just use g'(10) and h'(10).
So f'(10), pronounced "eff prime of ten", = 0 * 35 = 0.
If the question were asking for f(10) instead of f'(10) then you would use g(10) and h(10), ⇒-4*560=90.