Answer:
The correct answer to the following question will be "Physical Layer".
Explanation:
- The lowest layer of the OSI reference model is the physical layer. It's in charge of having to send bits from one desktop to the next.
- This layer isn't acquainted with the interpretation of the parts and is concerned with setting up a physical wireless connection and sending and receiving signals.
- This layer relies on aspects of the hardware, such as wires, transmitters, and network interface tokens.
Therefore, it will be the right answer.
A Peer-to-peer network architecture would work best for Edward and Matthew.
Although they have the option of creating a Client-Server type of network architecture, the number of people that they are currently working with would cost them a lot more than a peer-to-peer architecture.
One of the advantages of using a Peer-to-peer network architecture for a small network would be the access of files between all computers in the network. Even if one of the computers will fail, the other computers will still have access to the different files and information they will need to keep the company moving forward.
<u><em>[ Absolute ]</em></u><em> Addresses do not change if you copy them to a different cell.</em>
<u><em>[ Relative ]</em></u><em> </em><em>Addresses change depending on the cells you copy them to.</em>
Answer:
The answer is "SPAN"
Explanation:
The full form of SPAN port is "Switch Port Analyzer", which is used to designed specifically for the interface on a network device, that would be able to monitor all traffic passing across the entire device.
- The use of this port will also call the mirror ports, that is a popular way of gathering data traffic for tracking purposes.
- It is primarily used to access the bus switch and all interfaces, which is usually accessible from data transmission.
Answer:
% here x and y is given which we can take as
x = 2:2:10;
y = 2:2:10;
% creating a matrix of the points
point_matrix = [x;y];
% center point of rotation which is 2,2 here
x_center_pt = x(2);
y_center_pt = y(2);
% creating a matrix of the center point
center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));
% rotation matrix with rotation degree which is 45 degree
rot_degree = pi/4;
Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];
% shifting points for the center of rotation to be at the origin
new_matrix = point_matrix - center_matrix;
% appling rotation
new_matrix1 = Rotate_matrix*new_matrix;
Explanation:
We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.
