Answer: a) Emotional appeal
Explanation: Calls on feeling of human is referred as the emotion of the humans ,thus it is said to be an emotional appeal. Other appeals in the options are for the call on technical,logical or unexpected error reason and does not relate to the human audience needs or sympathies .But emotional appeal deals with these need on being called. So, option (a) is the correct option .
Answer:
False
Explanation:
The good example of pivoting is NOT changing the dimensions along the axis.
Answer:
The challenge of cost control
The challenge of competence
The challenge of reduced system delivery times.
Explanation:The Challenge of Cost control is a major challenge affecting the software engineering in the 21st century,the cost of Microchips and other hardware are constantly rising.
The challenge of competence is another major challenge affecting software engineering in the 21st century,as most software engineers lack the required competence to handle some of the issues facing softwares.
The challenge of reduced system delivery times is a major challenge likely to affect software engineering in the 21st century,as people required the software to be available in the shortest possible time.
Answer:
- food_category = {
- "Fruits": ["Apple", "Strawberries", "Orange"],
- "Vegetables": ["Carrots", "Peas", "Onions"],
- "Meats": ["Chicken", "Beef", "Mutton"]
- }
-
- for cat in food_category:
- output = cat + ": "
- for food in food_category[cat]:
- output += food + ", "
- print(output)
-
- answer = input("Do you want to add category or food (Y - Yes N - No): ")
-
- while(answer == "Y"):
- choice = input("New Category (N) or New Food (nf): ")
-
- if(choice == "N"):
- new_cat = input("Enter new category name: ")
- if(new_cat not in food_category):
- food_category[new_cat] = ""
- elif(choice == "nf"):
- cat = input("Enter category: ")
- new_food = input("Enter new food name: ")
- food_category[cat].append(new_food)
-
- answer = input("Do you want to add new category or food (Y - Yes N - No): ")
-
- print("All food categories: ")
- for cat in food_category:
- print(cat)
-
- selected_cat = input("Select a category to view the food list: ")
- output = ""
- for food in food_category[selected_cat]:
- output += food + ", "
- print(output)
Explanation:
The solution code is written in Python 3.
Firstly, create a food category dictionary data structure (Line 1 -5). Next, display all the food category and the food in each category (Line 7 - 11)
Next prompt user to feedback if they wish to add new category or new food (Line 13).
While the answer is yes prompt user to enter their choice, either category or food and use if else if statements to handle the choice made by the user. If the choice is new category, prompt user to enter new category name and check if the new category is already exist in the dictionary. If not, add that category to dictionary (Line 18 - 21).
If the choice is food, nf, prompt user to input food category and enter the new food name and add it to the food_category list (Line 22 - 25).
After that prompt user to enter if they wish to continue to add new data (Line 27).
After collecting all info from user, write a for loop to display all the categories (Line 29 - 31).
At last, prompt user to select a category and display all the food of the selected category (Line 33 - 37).
