2(4y+3)=16 I need help solving for "y" using the algabreic method
1 answer:
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You can use the Pythagorean Theorem to find the length of the third side AB (Identified as "x" in the figure attached in the problem), which says that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs:
a² = b²+c²
As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:
b = √(a²-c²) b = √(10²-4²)
b = 9.16
With these values, we can find the hypotenuse in the triangle "B":
x = √b²+c²
x = √(9.16)²+(4)²
x = 10
a² = b²+c²
As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:
b = √(a²-c²) b = √(10²-4²)
b = 9.16
With these values, we can find the hypotenuse in the triangle "B":
x = √b²+c²
x = √(9.16)²+(4)²
x = 10