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3 years ago

I need help with 7-14

Mathematics

1 answer:

aliina [53]3 years ago

5 0

7: $200<3x-y(28) where x represents each kids money out of it and y represents the parents pay.
8: 7.00>(is greater then or equal to) 0.75X + 1.29Y where X is the amount of bagels and Y is the amount of cream cheese containers.
9: $25 + $75>4X where X is the shirts
10: 720-120>(greater then or equal to) 32X where X is the number of people in each row
11: 2400= 2100+ X(1/20) where X is the value of all things sold.
12: 2000<(X7)-668 where X is the amount of cans in one day.
13: 100> 7X - 10Y where X equals the amount of months and Y equals the amount of CD's
14: $80 - $22> (greater than or equal to) 17X where x equals the amount of shirts.

first off sorry it took so long to answer, these long word questions are time consuming and i havent done them in a while so i had to refresh my memory, secondly the equations all end where i say the word "where", thirdly i am absolutely sure of all these answers except for the first one, the first one i am pretty sure i still got it but not 100%.

hope this helps.

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3 years ago

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2 years ago

Image below.<br> Explain

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No, It is not true

Step-by-step explanation:

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2 years ago

Read 2 more answers

Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to

bonufazy [111]

Answer:

-48

Step-by-step explanation:

Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square of Mx - Ly. In other words

$\int\limits_C {L(x,y)} \, dx + M(x,y) \, dy = \int\limits_0^2\int\limits_0^2 (M_x - L_y ) \, dx \, dy$

Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,

M(x,y) = 4x²y
Mx(x,y) = 8xy
L(x,y) = 10y²x
Ly(x,y) = 20xy
Mx - Ly = -12xy

Therefore, the line integral can be computed as follows

$\int\limits_C {10y^2x} \, dx + {4x^2y} \,dy = \int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy$

Using the linearity of the integral and Barrow's Theorem we have

$\int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy = -12 \int\limits_0^2\int\limits_0^2 xy \, dx \, dy = -12 \int\limits_0^2\frac{x^2y}{2} |_{x = 0}^{x=2} \, dy = -12 \int\limits_0^22y \, dy \\= -24 ( \frac{y^2}{2} |_0^2) = -24*2 = -48$

As a result, the value of the double integral is -48-

3 0

3 years ago