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gizmo_the_mogwai [7]
3 years ago
13

Given a triangle with c=1.6, B=125 degrees, and C= 9degrees Using the law of sines gives: b=

Mathematics
1 answer:
rusak2 [61]3 years ago
5 0
The answer would be b=8.378
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Can someone please help me with these math problems :)
just olya [345]
A)
1) v = 36
2) a = 2

B)
1) c = 22
2) I don’t know

C)
1) P = 2
2) b = 3

I’m not 100% sure these are right but I’m pretty sure :)
7 0
3 years ago
Can you guys distribute this problem and then figure out how many solutions does this problem have 5(m-3)=7m-17
Cloud [144]
                         5 (m - 3)  =  7m - 17

Eliminate
parentheses:        5m - 15  =  7m - 17

Subtract 5m
from each side:          - 15  =  2m - 17

Add 17
to each side:                  2  =  2m

Divide
each side
by  2 :                            1  =  m  

No more solutions.
Only one.

6 0
4 years ago
A plumber charges $70 per hour plus $40 dollars for the call. What does he charge for 4 hours of work
Varvara68 [4.7K]
First, let's create an equation for this problem. 
($70 × 4) + $40

Now, all you would have to do is solve it using the order of operation (PEMDAS).
($70 × 4) + $40 = $280 + $40
$280 + $40 = $320

The plumber charged $320. 

I hope this helps!
8 0
4 years ago
Read 2 more answers
How can one third x − 2 = one fourth x + 11 be set up as a system of equations?
timurjin [86]

Answer: (x-2) = (x+11)

------- -------

3 4

Step-by-step explanation:

First part is x-2 divided by on third. So the x-2 acts a the 1 so you put x-2 over 3. And you get:

(x-2)

--------

3

For the other side of the equation it is x +11 divide by 1/4. So the x+11 will act a the 1 in the fraction. And you will get:

(x+11)

--------

4

4 0
3 years ago
Read 2 more answers
Maths i need help with quadratics example (x-2)squared +1
Makovka662 [10]
                         (x - 2)² + 1 = 0
                 (x - 2)(x - 2) + 1 = 0
          x(x - 2) - 2(x - 2) + 1 = 0
x(x) - x(2) - 2(x) + 2(2) + 1 = 0
            x² - 2x - 2x + 4 + 1 = 0
                   x² - 4x + 4 + 1 = 0
                         x² - 4x + 5 = 0
                                        x = <u>-(-4) ± √((-4)² - 4(1)(5))</u>
                                                             2(1)
                                        x = <u>4 ± √(16 - 20)</u>
                                                        2
                                        x = <u>4 ± √(-4)
</u>                                                   2<u>
</u>                                        x = <u>4 ± 2i</u><u>
</u>                                                  2<u>
</u>                                        x = 2 ± i
                                        x = 2 + i    U    x = 2 - i
                                        The solution set is {2 ± i}.
<u />
5 0
3 years ago
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