Question

Which of these formulas is correctly rewritten from the original formula to solve for b? a = 3b - 2c?

Answer 1

-3b=-a-2c
b=(a-2c)/-3

Answer 2

Answer:

$b=\frac{a+2c}{3}$

Step-by-step explanation:

We have been given an equation $a=3b-2c$. We are supposed to solve the given equation for b.

First of all, we will switch sides of the given equation as:

$3b-2c=a$

Let us add $2c$ on both sides:

$3b-2c+2c=a+2c$

$3b=a+2c$

Divide both sides by 3:

$\frac{3b}{3}=\frac{a+2c}{3}$

$b=\frac{a+2c}{3}$

Therefore, our required equation wold be $b=\frac{a+2c}{3}$.