Ask question

Ask question

All categories

3 years ago

15

What is the area, in square centimeters, of the isosceles trapezoid below?

1 answer:

charle [14.2K]3 years ago

7 0

Both triangles area:
4.2 x 8.2 = 34.44

you don’t need to divide by two cause there’s two triangles anyways.

also, you get 8.2 by subtracting the total length by the top length. (13.5-5.3)

rectangle:
4.2 x 5.3 = 22.26

the total area is 56.7cm squared

You might be interested in

Two cars leave towns 750 kilometers apart at the same time and travel toward each other. One car's rate is 20 kilometers

Tanya [424]

Answer:

Step-by-step explanation:

add up their speed.

combined speed = x+ 1 x + 10

( 2 x + 10 )

Time = 5 hours

Distance = 750 miles

Distance = speed * time

( 2 x 10 )* 5 = 750

10 x + 50 = 750

10 x = 750 + -50

10 x = 700

/ 10

x= 70 mph Car A

Car B 70 + 10 = 80 mph

4 0

3 years ago

3.52 in expanded form

Scrat [10]

Step-by-step explanation:

3.52 =

3

+ 0.5

+ 0.02

hopes this helps you

6 0

2 years ago

Pls help will give the big brain award <br><br> +if you help more you get more brainliest

Effectus [21]

64 in2 is the answer

7 0

3 years ago

Read 2 more answers

George's page contains twice as many typed words as Bill's page and Bill's page contains 50 fewer words than Charlie's page. If

seropon [69]

The answer to this question is:

Bill's page initially contained 260 words.

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5

DanielleElmas [232]

Answer:

1

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that $csc(x)=1/sin(x)$ and $sec(x)=1/cos(x)$ .

Thus:

$\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}$

$=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }$

Let's do the first part first: (Recall how to divide fractions)

$\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}$

For the second term:

$\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}$

So, all together: (same denominator; combine terms)

$\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}$

Note the numerator; it can be derived from the Pythagorean Identity:

$sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)$

Thus, we can substitute the numerator:

$\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1$

Everything simplifies to 1.

7 0

2 years ago