Help me find the answer to this area of a kite problem

What is the length of the line? Choose 1 answer:

scoray [572]

Answer:

√29

Step-by-step explanation:

We can use the pythagorean theorem to find the length of this line. You can draw a vertical line downwards from the higher point and a horizontal line towards the left from the lower point. This will create a right triangle. Wd can count the lengths of the legs, getting 2 and 5. We can substitute these values in the pythagorean theorem:

a^2 + b^2 = c^2

2^2 + 5^2 = c^2

4 + 25 = c^2

c^2 = 29

c = √29

Since c is the hypotenuse and is the same length of the line, the line is √29 units long

6 0

3 years ago

What are the exact values of sin(2π/3radians) and cos(2π/3radians)?

maria [59]

Sin(2π/3radians) = sin(π/3radians) = (√3)/2cos(2π/3radians) = - cos(π/3radians) = 1/2

becuase 2π/3 + π/3 = π

6 0

2 years ago

Write a scenario to go with this equation. 5x – 2 = 28

Crazy boy [7]

Answer:

John planted flowers. For every 5 that grew per month 2 died. In how many months did 28 grow?

Step-by-step explanation:

Hope this is what u were looking for

8 0

2 years ago

Read 2 more answers

Tia and Ken sold snack bars and magazine subscriptions for the school fundraiser. Tia sold 16 snack bars and 4 magazine subscrip

Aliun [14]

Answer:

The value of the snack bar is $ 2 and that of the magazine subscription is 25 $

Step-by-step explanation:

We have a system of two equations and two unknowns, which would be the following:

let "x" be the cost of the snack bar

Let "y" be the cost of the magazine subscription

16 * x + 4 * y = 132

20 * x + 6 * y = 190 => y = (190 - 20 * x) / 6

replacing:

16 * x + 4 * (190 - 20 * x) / 6 = 132

16 * x + 126.66 - 13.33 * x = 132

2.66 * x = 132 - 126.66

x = 5.34 / 2.66

x = 2

for "y":

y = (190 - 20 * 2) / 6

y = 25

Which means that the value of the snack bar is $ 2 and that of the magazine subscription is 25 $

6 0

3 years ago

A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco

Brut [27]

Answer:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X_{A}=48250$ represent the mean of elementary teachers

$\bar X_{B}=45630$ represent the mean for secondary teachers

$s_{A}=3900$ represent the sample standard deviation for elementary teacher

$s_{B}=5530$ represent the sample standard deviation for secondary teachers

$n_{A}=26$ sample size selected

$n_{B}=24$ sample size selected

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{B}\leq 0$

Alternative hypothesis: $\mu_{A}-\mu_{B}>0$

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0

2 years ago