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Nana76 [90]
3 years ago
5

What is the multiple of 49 and 45

Mathematics
2 answers:
Serjik [45]3 years ago
8 0


You can make this easier by separating the numbers.

Let's split up 49 first.

You would split this into 40 and 9.

Then, split 45 into 40 and 5.

Multiply the  numbers from the ones place (5 and 9) to get 45.

Then multiply the numbers in the tens place (40 and 40).

If you do 4 times 4 it equals 16, and with the two 40's all you have to do is add two zeros., which makes it 1,600.

Then, add both of those numbers (1,600 and 45) up to get 1,645.

Anna35 [415]3 years ago
5 0
If you are asking for 45 times 49 then the answer is 2115

if you are asking fo the smallest number that 45 and 49 will multiply into the the answer is gotten by
45=7*5
49=7*7
answer=7*7*5=245
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Answer:

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Step-by-step explanation:

7 0
2 years ago
Could someone plz help I need the answers by tonight
Maksim231197 [3]

Answer:

7)  C) PQR ≈ TSR

8) B)  3

9) D) 102 ft

10) D) 21

11) C) 45

Step-by-step explanation:

7) C) PQR ≈ TSR

8) 2 * 6 = 12

so 4x = 12

      x = 3

9)

24/20 = x/85

x = 24 * 85 / 20

x = 202 ft

10)

QT/35 = 24/40

QT/35 = 3/5

QT = 35 * 3 / 5

QT = 21

11)

ΔKLM ≈ΔXYZ

9/4 = 2.25

So

XY = 9 ---> given

YZ = 7 * 2.25 = 15.75

XZ = 9 * 2.25  = 20.25

Perimeter ΔXYZ = 9 + 15.75 + 20.25 = 45

7 0
3 years ago
I need in depth help answering ​
Volgvan
What is the question
8 0
3 years ago
Write the decimal in fractional notation: 0.097 A 97/1000 B 97/10,000 C 970 /1000 D 97/10
jeyben [28]
If you would like to write 0.097 in fractional notation, you can do this like this:

0.097 = 97 / 1000 

The correct result would be <span>A 97/1000.</span>
3 0
3 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
Read 2 more answers
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