Rider dribbles the ball down 1/3 of the basketball court on the first day of practice. Each day after that he dribbled 1/3 of th
e way more than he did day before.
Draw number line to represent the court.
Partition the number line to represent How far rider dribbles on day one, two, 3
Draw number line to represent the court.
Partition the number line to represent How far rider dribbles on day one, two, 3
2 answers:
Answer with explanation:
It is given that:
Rider dribbles the ball down 1/3 of the basketball court on the first day of practice.
Also each day after that he dribbled 1/3 of the way more than he did day before.
Let the length of the basketball court be 'x' units.
So, in particular we choose x=1 units.
i.e. in table form we can represent the distance he dribbles as:
Day 1 1/3
Day 2 2/3
Day 3 3/3=1
Also, it could be represented in the number line we can see with the help of the figure attached to the answer.
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To make the input-output table, we need to plug in the given vaues of x's in the equation to get their corresponding values of y.
Let's plug in x = -2 in y = 6x +5. So,
y = 6( -2) + 5 = -12 + 5 = -7
Similarly for x = 0, y= 6(0) + 5 = 5
For x = 1, y = 6(1) + 5 = 6 + 5 = 11
For x = 4, y = 6(4) + 5 = 24 + 5 = 29
For x= 5, y = 6(5) + 5 = 30 + 5 = 35.
I am attaching the input -output table from the above result.
Hope this helps you!
Answer:
<u>Step-by-step explanation:</u>
The probability of Event B given Event A = the intersection of Event A and B divided by the probability of Event A. (see below for the symbols)
P(A) = (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1)
(2, 6), (2, 5), (2, 4), (2, 3), (2, 2), (2, 1)
(3, 6), (3, 5), (3, 4), (3, 3), (3, 2), (3, 1)
(4, 5), (4, 4), (4, 3), (4, 2), (4, 1)
(5, 4), (5, 3), (5, 2), (5, 1)
(6, 3), (6, 2), (6, 1)
= 30
P(B) = (1, 2), (2, 1) sum = 3
(1, 5), (2, 4), (3, 3), (4, 2), (5, 1) sum = 6
(3, 6), (4, 5), (5, 4), (5, 4), (6, 3) sum = 9
(6, 6) sum = 12
= 12
P(A ∩ B) = (1, 2), (2, 1)
(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)
(3, 6), (4, 5), (5, 4), (5, 4), (6, 3)
= 11
Answer:
Step-by-step explanation:
<h3><u>Given that:</u></h3>Exterior angle of L = 5x + 12
M = 3x - 2
N = 50
<h3><u>Statement:</u></h3>- Exterior angle is equal to the sum of non-adjacent interior angles.
So, the exterior angle that is adjacent to L is equal to the sum of non-adjacent sides (M and N) of the triangle.
Here,
Exterior angle of L = M + N
5x + 12 = 3x - 2 + 50
5x + 12 = 3x + 48
Subtract 12 to both sides
5x = 3x + 48 - 12
5x - 3x = 36
2x = 36
Divide 2 to both sides
x = 18
So,
<h3><u>Measure of angle M:</u></h3>= 3x - 2
= 3 (18) - 2
= 54 - 2
= 52°
Now,
<h3><u>Measure of angle L:</u></h3><u>We know that,</u>
- Sum of all the interior angles of triangle is 180 degrees.
L + M + N = 180°
L + 52 + 50 = 180
L + 102 = 180
Subtract 102 to both sides
L = 180 - 102
L = 78°