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Luda [366]
1 year ago
10

Can you please solve the last question… number 3! Thanks!

Mathematics
1 answer:
Lunna [17]1 year ago
3 0

Let us break the shape into two triangles and solve for the unknowns.

The first triangle is shown below:

We will use the Pythagorean Theorem defined to be:

\begin{gathered} c^2=a^2+b^2 \\ where\text{ c is the hypotenuse and a and b are the other two sides} \end{gathered}

Therefore, we can relate the sides of the triangles as shown below:

25^2=y^2+16^2

Solving, we have:

\begin{gathered} y^2=25^2-16^2 \\ y^2=625-256 \\ y^2=369 \\ y=\sqrt{369} \\ y=19.2 \end{gathered}

Hence, we can have the second triangle to be:

Applying the Pythagorean Theorem, we have:

22^2=x^2+19.2^2

Solving, we have:

\begin{gathered} 484=x^2+369 \\ x^2=484-369 \\ x^2=115 \\ x=\sqrt{115} \\ x=10.7 \end{gathered}

The values of the unknowns are:

\begin{gathered} x=10.7 \\ y=19.2 \end{gathered}

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Answer:  \displaystyle y= \frac{2\text{x}}{4\text{x} - 1}

============================================

Work Shown:

8\text{x}y= 2(2\text{x} + y)\\\\8\text{x}y= 4\text{x} + 2y\\\\8\text{x}y - 2y= 4\text{x}\\\\y(8\text{x} - 2)= 4\text{x}\\\\y= \frac{4\text{x}}{8\text{x} - 2}\\\\y= \frac{2*2\text{x}}{2(4\text{x} - 1)}\\\\y= \frac{2\text{x}}{4\text{x} - 1}\\\\

---------------

Explanation:

The idea is to first get all the y terms to one side. I did this by subtracting 2y from both sides in the third step.

Then factor out y and divide both sides by (8x-2)

Afterward there's the optional steps of simplifying (as shown in the final two steps).

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2 years ago
5)<br> Solve for x.<br> 2x + 16 = 3(x - 9)<br> My Answer:
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Answer:

Step-by-step explanation:

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3 years ago
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