Let us break the shape into two triangles and solve for the unknowns.
The first triangle is shown below:
We will use the Pythagorean Theorem defined to be:
![\begin{gathered} c^2=a^2+b^2 \\ where\text{ c is the hypotenuse and a and b are the other two sides} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%20where%5Ctext%7B%20c%20is%20the%20hypotenuse%20and%20a%20and%20b%20are%20the%20other%20two%20sides%7D%20%5Cend%7Bgathered%7D)
Therefore, we can relate the sides of the triangles as shown below:
![25^2=y^2+16^2](https://tex.z-dn.net/?f=25%5E2%3Dy%5E2%2B16%5E2)
Solving, we have:
![\begin{gathered} y^2=25^2-16^2 \\ y^2=625-256 \\ y^2=369 \\ y=\sqrt{369} \\ y=19.2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%5E2%3D25%5E2-16%5E2%20%5C%5C%20y%5E2%3D625-256%20%5C%5C%20y%5E2%3D369%20%5C%5C%20y%3D%5Csqrt%7B369%7D%20%5C%5C%20y%3D19.2%20%5Cend%7Bgathered%7D)
Hence, we can have the second triangle to be:
Applying the Pythagorean Theorem, we have:
![22^2=x^2+19.2^2](https://tex.z-dn.net/?f=22%5E2%3Dx%5E2%2B19.2%5E2)
Solving, we have:
![\begin{gathered} 484=x^2+369 \\ x^2=484-369 \\ x^2=115 \\ x=\sqrt{115} \\ x=10.7 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20484%3Dx%5E2%2B369%20%5C%5C%20x%5E2%3D484-369%20%5C%5C%20x%5E2%3D115%20%5C%5C%20x%3D%5Csqrt%7B115%7D%20%5C%5C%20x%3D10.7%20%5Cend%7Bgathered%7D)
The values of the unknowns are: