Please help me quick!!!!

For a set of data, r = 0.27. Which is true about the correlation of the variables?

Harman [31]

The correlation is a weak positive correlation

6 0

3 years ago

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What are the names of the numerical system for numbers 3 to 16?

denis-greek [22]

The Numerical system for the numbers is given by Positional Notation

Step-by-step explanation:

numerical system for 3 is TERNARY.
Numerical System for 4 is QUATERNARY.
Numerical System for 5 is QUINARY.
Numerical System for 6 is SENARY.
Numerical System for 7 is SEPTENARY.
Numerical System for 8 is OCTAL.
Numerical System for 9 is NONARY.
Numerical System for 10 is DENARY or DECIMAL.
Numerical System for 11 is UNDECIMAL.
Numerical System for 12 is DUODECIMAL.
Numerical System for 13 is TRIDECIMAL.

4 0

4 years ago

What is the slope of the equation y = 5x - 7? o -7 o 7.

Cerrena [4.2K]

Answer:

slope = 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x - 7 ← is in slope- intercept form

with slope m = 5

5 0

3 years ago

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Research seems to indicate that the optimum group size for problem solving is _____ members. Select one: a. 2 b. 15 c. 5 d. 25

Daniel [21]

Answer:

Correct answer is (c). 5

Step-by-step explanation:

It is important to note that solving problem requires techniques and intelligent people most especially when problem are complex or hard in nature. It is therefore important to ensure the numbers of problem solving experts should not be undersized than required to avoid over burden them and should not be too large to avoid conflict in their individual resolutions. Hence, most scientific reports state that problem solving experts should be within 3 to 5 members and as for this question, the optimum is 5 members.

6 0

3 years ago

Students in a representative sample of 69 second-year students selected from a large university in England participated in a stu

Serhud [2]

Answer:

95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].

Step-by-step explanation:

We are given that for the 69 second-year students in the study at the university, the sample mean procrastination score was 41.00 and the sample standard deviation was 6.89.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean procrastination score = 41

s = sample standard deviation = 6.89

n = sample of students = 69

$\mu$ = population mean estimate

Here for constructing 95% confidence interval we have used One-sample t test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.9973 < $t_6_8$ < 1.9973) = 0.95 {As the critical value of t at 68 degree

of freedom are -1.9973 & 1.9973 with P = 2.5%}

P(-1.9973 < $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ < 1.9973) = 0.95

P( $-1.9973 \times{\frac{s}{\sqrt{n} } }$ < ${\bar X -\mu}$ < $1.9973 \times{\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.9973 \times{\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.9973 \times{\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ =[ $\bar X-1.9973 \times{\frac{s}{\sqrt{n} } }$ , $\bar X+1.9973 \times{\frac{s}{\sqrt{n} } }$ ]

= [ $41-1.9973 \times{\frac{6.89}{\sqrt{69} } }$ , $41+1.9973 \times{\frac{6.89}{\sqrt{69} } }$ ]

= [39.34 , 42.66]

Therefore, 95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].

5 0

3 years ago