Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
1/2 divided by 1/6 is 3 or 3/1
you have to divide 2 to 6 and u get 3
Let
<span>p ----------------> is the perimeter of the base
</span><span>h ---------------> is the height
</span><span>BA-------------> is the area of the bases
</span><span>LA--------------> is the lateral area
we know that surface area is </span><span>the sum of base areas plus lateral areas
</span><span>then
SA=[BA]+P*h
but remember that
LA=P*h
then
SA=</span>[BA]+LA----------> SA=BA+LA
the answer are the options B.) SA=BA+LA and the option D.) SA=BA+ph
Answer:
By multiplying each ratio by the second number of the other ratio, you can determine if they are equivalent. Multiply both numbers in the first ratio by the second number of the second ratio. For example, if the ratios are 3:5 and 9:15, multiply 3 by 15 and 5 by 15 to get 45:75.
Let's use a for number of days when he shot 50 shots and b for number of days when he shot 100 shots.
We have:
a + b = 20
We also know that he shot total of 1250 shots:
50a + 100 b = 1250
We have two equations. We can solve them for a and b. Let's rearange first equation for a:
a= 20 - b
We insert this into second equation:
50 * (20 - b ) + 100b = 1250
1000 - 50b + 100b = 1250
50b = 250
b = 5
a = 20 - 5
a = 15
Mark shot 100 shots on 5 days.