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Maurinko [17]
3 years ago
8

in a discount basis loan interest is paid at the time the loan is made by deducting the amount from the loan

Mathematics
1 answer:
stepladder [879]3 years ago
4 0
Yes I believe not really sure what the question is??
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Find the variation constant and an equation of variation where y varies directly as x and y=24 when x=3.
Kay [80]

Answer:

8

Step-by-step explanation:

y=x, y=kx, k is a constant, k/x=y/x, k=y/x, k=24/3, k=8

8 0
3 years ago
What is the probability of getting 5 baskets ina row out of 10 shots
Fiesta28 [93]
The probability would be 50%
4 0
3 years ago
A repeated-measures study comparing two treatments with n = 4 participants produces md = 2 and ss = 75 for the difference scores
valentinak56 [21]

The estimated standard error for the sample mean difference is  2.5 .

According to the question

A repeated-measures study comparing two treatments

n = 4

MD(mean difference) = 2

SS (sum of square) = 75

Now,

error for the sample  

Formula for standard error

S^{2} = \frac{SS}{n-1}

by substituting the value

S^{2} = \frac{75}{4-1}

S^{2} = \frac{75}{3}

S² = 25

S = 5 (s is never negative)

Standard error of the estimate for the sample mean difference

As

The standard error of the estimate is the estimation of the accuracy of any predictions.

The formula for standard error of the mean difference

standard error of the mean difference  =\frac{standard\\\ error}{\sqrt{n} }  

standard error of the mean difference = \frac{5}{\sqrt{4} }  

standard error of the mean difference = 2.5

Hence, the estimated standard error for the sample mean difference is  2.5 .

To know more about estimated standard error here:

brainly.com/question/14524236

#SPJ4

5 0
1 year ago
A group of students wanted to investigate the claim that the average number of text messages sent yesterday by
Likurg_2 [28]
First we need to write the null and alternate hypothesis for this case.

Let x be the average number of text message sent. Then

Null hypothesis: x = 100
Alternate hypothesis: x > 100

The p value is 0.0853

If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.

If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.

If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
7 0
3 years ago
A rectangular parking lot has an area of 2/3 of a square kilometer. The width is 1/2 of a kilometer. What is the length, in kilo
jeka57 [31]
Area = length x width
 replace the known information into the equation:

area = 2/3
width = 1/2

so now the formula looks like:

2/3  = 1/2 x L

to solve for L we divide both sides by 1/2

L = 2/3 / 1/2 which  = 2/3 * 2/1 = 4/3 = 1 and 1/3 km
6 0
3 years ago
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