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3 years ago

Help me with 10-16 pleaseeee

Mathematics

2 answers:

Vikentia [17]3 years ago

5 0

10)

3.09; 3.008; 3.18; 3.825

11)

0.2; 0.275; 0.572; 0.725

12)

6.108; 6.230; 6.318; 6.32

13)

0.456; 0.645; 0.654; 1.345

14)

2.48 > 2.471 > 2.463

15)

5.723 < 5.724 < 5.725

16)

7.64 < 7.65 < 7.68

Setler79 [48]3 years ago

3 0

Answer:

10.) 3.09 3.18 3.008 3.825 16.) 7.68

Step-by-step explanation:

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What is the name of segment BD ?!

Alenkasestr [34]

Answer:

diameter

Step-by-step explanation:

BD is the diameter of the circle.

4 0

3 years ago

Please help :0

Zinaida [17]

Mult. f(x) = x^4 by 2 will stretch the graph vertically by a factor of 2.
Thus, eliminate (a) and (b).

Mult. x by (1/4) will stretch the graph horiz. by a factor of 4. Thus, (c) is the correct answer.

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3 years ago

Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]

alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

$\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]$

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)² = 3√6

Therefore, the unit vector is

$\frac{[7,2,-1]}{3\sqrt{6} }$

[ $\frac{7}{3\sqrt{6} }$ , $\frac{2}{3\sqrt{6} }$ , $\frac{-1}{3\sqrt{6} }$ ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ $\frac{-7}{3\sqrt{6} }$ , $\frac{-2}{3\sqrt{6} }$ , $\frac{1}{3\sqrt{6} }$ ]

In conclusion, the two unit vectors are;

[ $\frac{7}{3\sqrt{6} }$ , $\frac{2}{3\sqrt{6} }$ , $\frac{-1}{3\sqrt{6} }$ ]

and

[ $\frac{-7}{3\sqrt{6} }$ , $\frac{-2}{3\sqrt{6} }$ , $\frac{1}{3\sqrt{6} }$ ]

<em>Hope this helps!</em>

7 0

2 years ago

Solve the equation for y. 8x – 9y = 11

Vikentia [17]

8x - 9y = 11 (subtract 8x from each side)

- 9y = -8x + 11 (divide -9 from each side)

$\frac{-9y}{-9} = \frac{-8x+11}{-9}$

y = $\frac{-8}{-9} x - \frac{11}{9}$

D. $y=\frac{8}{9} x - \frac{11}{9}$

6 0

3 years ago

point a is at (-7 5) and point c is at (5 -1). find the coordinates of point b on line ab such that ab is 5 times as long as bc

WARRIOR [948]

Step-by-step explanation:

Let the coordinates of point b be (x,y).

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Solving we can get

$x=-\frac{-11+\sqrt{-4y^2-10y+25}}{2},\:x=\frac{\sqrt{-4y^2-10y+25}+11}{2}$ '

However, we do need either x or y coordinate of point b to find the other.

5 0

3 years ago