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ZanzabumX [31]
2 years ago
14

HELP PLEASEEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics
1 answer:
umka21 [38]2 years ago
3 0

Answer:

The solution set to the absolute value is:

S = \{x \in \mathbb{R}| x \ge 0\} or S = [0, +\infty)

Negative real numbers are not included in the solution set, as for x < 0, |x| = - x.

Step-by-step explanation:

From Mathematics, we know that absolute values are defined by the following characteristics:

1) For x \ge 0, |x| = x

2) For x < 0, |x| = - x

Then, if |x| = x, then the solution set to the absolute value is:

S = \{x \in \mathbb{R}| x \ge 0\} or S = [0, +\infty)

Negative real numbers are not included in the solution set, as for x < 0, |x| = - x.

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Answer:
a=9

Explanation:
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a/1=9root2/root2
a/1=9
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3 years ago
Heather sampled the ages of 50 randomly selected people that frequented a store and obtained a mean of 24. She constructed a 95%
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2 years ago
Use the general slicing method to find the volume of the following solids. The solid whose base is the region bounded by the cur
Y_Kistochka [10]

Answer:

The volume is V=\frac{64}{15}

Step-by-step explanation:

The General Slicing Method is given by

<em>Suppose a solid object extends from x = a to x = b and the cross section of the solid perpendicular to the x-axis has an area given by a function A that is integrable on [a, b]. The volume of the solid is</em>

V=\int\limits^b_a {A(x)} \, dx

Because a typical cross section perpendicular to the x-axis is a square disk (according with the graph below), the area of a cross section is

The key observation is that the width is the distance between the upper bounding curve y = 2 - x^2 and the lower bounding curve y = x^2

The width of each square is given by

w=(2-x^2)-x^2=2-2x^2

This means that the area of the square cross section at the point x is

A(x)=(2-2x^2)^2

The intersection points of the two bounding curves satisfy 2 - x^2=x^2, which has solutions x = ±1.

2-x^2=x^2\\-2x^2=-2\\\frac{-2x^2}{-2}=\frac{-2}{-2}\\x^2=1\\\\x=\sqrt{1},\:x=-\sqrt{1}

Therefore, the cross sections lie between x = -1 and x = 1. Integrating the cross-sectional areas, the volume of the solid is

V=\int\limits^{1}_{-1} {(2-2x^2)^2} \, dx\\\\V=\int _{-1}^14-8x^2+4x^4dx\\\\V=\int _{-1}^14dx-\int _{-1}^18x^2dx+\int _{-1}^14x^4dx\\\\V=\left[4x\right]^1_{-1}-8\left[\frac{x^3}{3}\right]^1_{-1}+4\left[\frac{x^5}{5}\right]^1_{-1}\\\\V=8-\frac{16}{3}+\frac{8}{5}\\\\V=\frac{64}{15}

5 0
3 years ago
You have two credit cards. One has a balance of $3,745.00 at a 6.25% APR and the other has a balance of $1,045.00 and is depende
alexira [117]

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7 0
2 years ago
Read 2 more answers
The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are ( , ). The coordinates of the point that is
AURORKA [14]

Answer:

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Step-by-step explanation:

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It should be an L shape.

7 0
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