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ZanzabumX [31]
3 years ago
14

HELP PLEASEEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

The solution set to the absolute value is:

S = \{x \in \mathbb{R}| x \ge 0\} or S = [0, +\infty)

Negative real numbers are not included in the solution set, as for x < 0, |x| = - x.

Step-by-step explanation:

From Mathematics, we know that absolute values are defined by the following characteristics:

1) For x \ge 0, |x| = x

2) For x < 0, |x| = - x

Then, if |x| = x, then the solution set to the absolute value is:

S = \{x \in \mathbb{R}| x \ge 0\} or S = [0, +\infty)

Negative real numbers are not included in the solution set, as for x < 0, |x| = - x.

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Based in the diagram which statement is true
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14. congruent means "THE SAME" so it will be "A" because there all the same letter.

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7 0
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Help with these questions please ‼️
NNADVOKAT [17]

Write two equations to model the growth of each tree, and set the equal to each other.

Let x equal the years.

For Type A, the equation is 3x+48 because the tree grows at 3 inches per year and, it started at 4 feet (48 in).

For Type B, the equation is x+72 because the tree grows at 1 inch per year, and it started at 6 feet (72 in).

3x+48=x+72

<em>*Isolate the variable by subtracting x from each side*</em>

2x+48=72

<em>*Subtract 48 from both sides*</em>

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Hope this helps!!

6 0
3 years ago
Threee is a number divided by 6
Serhud [2]

Answer:

18

Step-by-step explanation:

the answer to what divided by 6 equals 3 is 18 you can prove his by taking 18 and dividing it by 6 and you will see that the answer is 3 for the future reference you when you presented with a problem like what divided by 6 equals 3 all you have to do is multiply the two known numbers together

7 0
3 years ago
Which is the correct way to solve the given equation
Karolina [17]

Option 2. x = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} shows the correct way to use the quadratic formula to solve the given equation.

Step-by-step explanation:

Step 1:

For an equation of the form ax^{2} +bx+c=0 the solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Here a is the coefficient of x^{2}, b is the coefficient of x and c is the constant term.

x^{2} -4x=21 can also be written as x^{2} -4x-21=0.

Comparing x^{2} -4x-21=0 with ax^{2} +bx+c=0, we get that a is 1, b is -4 and c is -21.

To get the solution, we substitute the values of a, b, and c in x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

Substituting the values, we get

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}= \frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.

\frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.

This is option 2.

7 0
4 years ago
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