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Aleks04 [339]
3 years ago
5

43 dollar dinner, 18% gratuity

Mathematics
1 answer:
rewona [7]3 years ago
4 0
$7.74

$43 * 18%
or
43 * 0.18
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Mazyrski [523]
The answer is w + 4 > -12
4 0
2 years ago
Solve for m and show your work. 4n=3m-1
Bad White [126]
4n = 3m - 1

4n = 3m - 1
Subtract 3m from both sides.
-3m + 4n = -1
Subtract 4n from both sides.
-3m = -4n - 1
Divide both sides by -3.
m = 4/3n + 1/3

m = 4/3n + 1/3
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3 years ago
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You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in
jeka57 [31]

Answer:

You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, <em>r</em> = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, <em>c</em> = 3.

The distribution of the statistic \chi^{2} is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.

Compute the degrees of freedom as follows:

df = (r-1)(c-1)=(2-1) \times (3-1) = 2

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011

Decision rule:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

The significance level is, <em>α</em> = 0.05.

<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."

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Answer:

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Step-by-step explanation:

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Consider the expression.
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