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3 years ago

14

If m ACB =(11x-32),find the value of x

1 answer:

Digiron [165]3 years ago

8 0

Answer: x= acb/11 + 32/11

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

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Solve the following quadratic function by utilizing the square root method. f(x) = 1 - x2 x = + [?]

faltersainse [42]

Answer:

Step 1) y=16-x2. Swap the sides so that all terms of the variables are on the left side. Step 2) 16-x_{2}=y. Subtract 16 from both sides. Step 3) -x_{2}=y-16 Divide the two sides by -1. Step 4). \frac{-x_{2}}{-1}=\frac{y-16}{-1} Dividing by -1 undoes the multiplication by -1. Step 5). x_{2}=\frac{y-16}{-1} Step 6) dived y-16 by -1 And the final answer = x_{2}=16-y

Step-by-step explanation:

7 0

2 years ago

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The area of a square is 64 n 36square units. What is the side length of one side of the square? 8 nt 6 units 8 n Superscript 18

tamaranim1 [39]

Answer:

8n18

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If you graph y=2x+1 and y=x+1 how many times would the two lines intersect

krok68 [10]

Given that they follow the format for straight lines and are therefore straight lines, they would only intersect once and that would be at (0,1) where they both have a y intersect.

Hope this helps :)

3 0

3 years ago

Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?

Shtirlitz [24]

The equation that has the solution $x = \frac{5 \pm \sqrt{7}}{3}$ is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

$x = \frac{5 \pm \sqrt{7}}{3}$

The solution to a quadratic equation is

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b = -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution $x = \frac{5 \pm \sqrt{7}}{3}$ is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

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7 0

1 year ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago