(<em>q = quarters, n = nickles</em>)
<u>First, create your system of equations:</u>
25q + 5n = 535 cents
n = 2q - 5
<u>Second, Substitute for n:</u>
25q + 5(2q - 5) = 535
<u>Simplify:</u>
25q + 10q - 25 = 535
<u>Simplify to solve for q:</u>
35q=560
q=16
<u>Next, solve for n by plugging the value of q back into the equation:</u>
n=2q - 5
n=32-5
n=27
There would be 16 quarters and 27 nickles.
<em>Hoped this helped!</em>
Answer:
Hope this is what you are looking for! :)
Answer:
9d^2/(2d + 4).
Step-by-step explanation:
18d^2 / (4d + 8)
First factorise the denominator:
= 18d^2 / 4(d + 2)
The GCF of 18 and 4 is 2 so this simplifies to:
9d^2/2(d + 2)
= 9d^2/(2d+ 4).
Answer:
34
Step-by-step explanation:
The Fibonacci sequence is the last 2 numbers added so
21+x=55 (x being 9th term)
x= (Subtract 21 from both sides)
34
Answer:
i know a in one of the answer and i think i mean i think b dont take me at my word on b though i think it is
Step-by-step explanation: