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almond37 [142]
3 years ago
15

Is the histogram uniform, symmetric, or skewed?

Mathematics
1 answer:
hodyreva [135]3 years ago
8 0
A histogram is a graph used to present ranges of data. In contrast to bar graphs or vertical graphs, these are more used in displaying complex and higher statistical data ranges. Moreover, the illustration is Uniform. Uniform in that it portrays that the data is in a rectangular shaped form. 
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POSSIBLE POINTS: 15
almond37 [142]
There’s 355 milliliters of soda in one can
7 0
3 years ago
Marc ordered a rug. He gave a deposit of 30% of the cost and will pay the rest when the rug is delivered. If the deposit was $75
ra1l [238]

Answer: Marc still owes $175

Step-by-step explanation:

Let x represent the cost of the rug.

Marc ordered a rug and gave a deposit of 30% of the cost and will pay the rest when the rug is delivered. This means that the amount of money that he deposited

for the rug is

30/100 × x = 0.3 × x = 0.3x

If the deposit was $75, it means that

0.3x = 75

x = 75/0.3 = 250

The cost of the rug is $250

The amount that Marc still owes would be

250 - 75 = $175

6 0
3 years ago
Linear function, pls help
True [87]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
A coordinate grid with 2 lines. One line, labeled f(x) passing through (negative 3, 3), (0, 3), and the point (4, 3). The other
Lyrx [107]

Answer:

x = 4

Step-by-step explanation:

It is stated that f(x) passes through

(-3, 3), (0, 3), (4, 3)

and g(x) passes through

(-4, -3), (0, 0), (4, 3)

Therefore, both functions pass through (4, 3). That is, the input value x = 4 produces the same output value y = 3 for the two functions.

8 0
4 years ago
Read 2 more answers
What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


8 0
3 years ago
Read 2 more answers
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