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Mnenie [13.5K]
3 years ago
9

Suppose you have the following recursion formula a1 = 1, a2 = 2, and an = a(n - 1)+ a(n - 2) for integers n ≥ 3. How would you d

etermine the next three terms?
Mathematics
1 answer:
Firlakuza [10]3 years ago
6 0
\left\{\begin{array}{ccc}a_1=1\\a_2=2\\a_n=a_{n-1}+a_{n-2}&for\ n\geq3\end{array}\right\\\\a_3=a_{3-1}+a_{3-2}=a_2+a_1\to a_3=2+1=3\\\\a_4=a_{4-1}+a_{4-2}=a_3+a_2\to a_4=3+2=5\\\\a_5=a_{5-1}+a_{5-2}=a_4+a_3\to a_5=5+3=8\\\vdots
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Biweekly salary last year algebraically will be S = (27)A.  Semimonthly salary this year algebraically will be S = ( A + R )6.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that Last year, Andrea's annual salary was A dollar and she was paid biweekly. This year she received a raise of R dollars per year. She is now paid semimonthly.

Biweekly salary last year algebraically will be:-

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Semimonthly salary this year algebraically will be:-

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Therefore, the biweekly salary last year algebraically will be S = (27)A.  Semimonthly salary this year algebraically will be S = ( A + R )6.

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Math pls help it says there is a cone but there isn't.​
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See explanation

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