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3 years ago

Question 7 is kicking my butt. One one good with percents ?

Mathematics

2 answers:

Illusion [34]3 years ago

7 0

32%
After 15 and 20%
The process would be 1156
Discount of 255 and 289

1156/1700=68
100-68=32

nikklg [1K]3 years ago

4 0

This could be wrong but i am pretty sure it will be a 35% decrease losing $29.75

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There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one

diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

$P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02$

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01$

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05$

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C$

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0

3 years ago

What is 18+ (8+4-9)= Please show step by step

8_murik_8 [283]

Answer: 21

Reasoning:

5 0

3 years ago

Read 2 more answers

A theater has a discount pass that cost nine dollars with the past admission is $6.50 per movie. mike tyrell and juanita all bou

tia_tia [17]

Answer:

They saw 24 movies.

Step-by-step explanation:

The question is incomplete so the complete question is below:

A theater has a discount pass that cost nine dollars with the pass, admission is $6.50 per movie. Mike, Tyrell and Juanita all bought a pass and went to see movies together they spent a total of $183. Write and solve an equation to find out how many movies they saw.

Now, to find the number of movies they saw.

Let the number of movies they saw be $x.$

Discount pass = $9.

With the pass admission per movie is $6.50.

Total number of people = 3.

Total money spent = $183.

So, to get the number of movies they saw we write an equation:

$3(9)+6.50(x)=183$

Now, to solve the equation:

$3(9)+6.50(x)=183$

$27+6.50x=183$

Subtracting on both sides by 27 we get:

$6.50x=156$

Dividing both sides by 6.50 we get:

$x=24.$

Therefore, they saw 24 movies.

4 0

3 years ago

Which cube root function is always decreasing as x increases?

kvasek [131]

The answer is O f(x) =-35x+5

5 0

3 years ago

Which of the following is true of the discriminant for the graph below?

Sonbull [250]

Answer:

Option C. It is zero

Step-by-step explanation:

The graph represents a quadratic equation

The quadratic equation has the form ⇒a x² + b x + c

The discriminant of the quadratic equation is D = b² - 4ac

From the discriminant of the quadratic equation, we can know the type of roots of the quadratic equation.

If D > 0 ⇒ Two real roots.
If D = 0 ⇒ one real roots
If D < 0 ⇒ Two imaginary roots.

The roots of the quadratic equation are the x-intercepts of the function.

As shown at the figure, the quadratic equation has only one point of intersection with the x-axis

So, the function has only one root ⇒ D = 0

So, the discriminant of the quadratic equation = 0

The answer is option C. It is zero

7 0

3 years ago