Answer:
There are 60 monkeys in the Zoo
Step-by-step explanation:
In this question, we are asked to calculate the number of monkeys in a Zoo given some information to use.
Let’s have the total number of monkeys be m.
60% are going monkeys. This means number of young monkeys is 0.6m.
The number of baby and old monkeys is obviously 0.4m.
Ratio of baby to old monkeys is 3:1. This means if we splitter 0.4m into 4, number of baby monkeys is 0.3m while number of old monkeys is 0.1m
Now, subtracting the number of baby monkeys from young monkeys give a total of 18 monkeys.
Let’s project this mathematically;
This means ;
0.6m - 0.3m = 18
0.3m = 18
m = 18/0.3
m = 60
There are 60 monkeys in the zoo
Answer:
The value for r is 19.1 cm
Step-by-step explanation:
We have been given that s = 16 cm, θ = 48° and we have to find the radius r.
We know the relation
Hence, first of all convert the angle in radian
θ = 48°= 0.837758 radian
Therefore, we have
First let's make the denominators of the fractions equal.
To do this, we have to find a number which both 5 and 7 divide into.
The smallest number that does this is 35.
2 --> Multiply the numerator by 7
--
5 --> Multiply the denominator by 7 to get 35
= 14/35
1 --> Multiply the numerator by 5
--
7 --> Multiply the denominator by 5 to get 35
= 5/35
Joe has eaten 14/35 and James has eaten 5/35.
14 / 5 = 2.8
<u>Joe has eaten 2.8 (or 2 4/5) times more pizza than James.</u>
h(x) = 3 * (2)^x
Section A is from x = 1 to x = 2
h(1) = 3 * (2)^1 = 3 * 2 = 6
h(2) = 3 * (2)^2 = 3 * 4 = 12
so
the average rate of change = (12 - 6)/(2 - 1) = 6
Section B is from x = 3 to x = 4
h(3) = 3 * (2)^3 = 3 * 8 = 24
h(4) = 3 * (2)^4 = 3 * 16 = 48
so
the average rate of change = (48 - 24)/(4 - 3) = 24
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)
the average rate of change of section B is 24 and the average rate of change of section A is 6
So 24/6 = 4
The average rate of change of Section B is 4 times greater than the average rate of change of Section A
It's exponential function, not a linear function; so the rate of change is increasing.
C(15, 7)
(15 * 14 * 13 * 12 * 11 * 10 * 9)/(7 * 6 * 5 * 4 * 3 * 2 * 1) = 6435 groups
