Answer:
The mother (Rhoda) is 46 years old.
The daughter (Tenica) is 18 years old
Step-by-step explanation:
Let the age of the mother (Rhoda) be m
Let the age of the daughter (Tenica) be d.
The sum of Rhonda and her daughter Tenica’s age is 64. This can be written as:
m + d = 64 ... (1)
The difference in their ages is 28. This can be written as:
m – d = 28 ... (2)
From the above illustrations, the equation obtained are:
m + d = 64 ... (1)
m – d = 28 ... (2)
Solving by elimination method:
Add equation 1 and 2 together
. m + d = 64
+ m – d = 28
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
2m = 92
Divide both side by 2
m = 92/2
m = 46
Substitute the value of m into any of the equation to obtain the value of d. Here, we shall use equation 1
m + d = 64
m = 46
46 + d = 64
Collect like terms
d = 64 – 46
d = 18
Therefore, the mother (Rhoda) is 46 years old and the daughter (Tenica) is 18 years old.
Car A consumes 25 gallon and car B consumes 15 gallon.
Step-by-step explanation:
Given,
The fuel efficiency of car A = 20 miles per gallon.
The fuel efficiency of car B = 15 miles per gallon.
In a week, two cars went 725 miles and consumed 40 gallons.
To find the consumption of each car in that week.
Let,
Car A consumed x gallon
Car B consumed y gallon.
According to the problem,
x+y = 40 ----- (1)
20x+15y = 725
or, 4x+3y = 145 -------- (2)
From (1) we get, x = 40-y
Putting the value of x in (2) we get,
4(40-y)+3y = 145
or, 160-4y+3y = 145
or, -y = 145-160
or, y = 15
From (1) we get, x = 40-15 = 25
Hence,
Car A consumes 25 gallon and car B consumes 15 gallon.
Answer:
53% or 0.53 or 53/100
Step-by-step explanation:
<span>In this case, that would be 13,000.</span>
Answer:
-31/8
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