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love history [14]
3 years ago
14

Find the value of the variable. If your answer is not an integer, leave it in simplest radical form.

Mathematics
1 answer:
Fed [463]3 years ago
6 0
It is the square root of 2
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Consider the quadratic equation x2=4x-5. How many solutions does the equation have
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The quadratic formula is =(-b+-sqrt(b^2-4ac))/2a
as you notice the term under the square root is b^2-4ac if it is postive then the equation clearly will have two real soultions if it is negative then the equation will have two imaginary soultion if it is zero then the the equation will have one soultion
so let us calculate b^2-4ac for our given equation
x^2=4x-5 so let us write it in general form which is ax^2+bx+c=0
subtracting 4x from both sides
x^2-4x=-5
adding 5 to both sides
x^2-4x+5=0
a=1,b=-4,c=5
b^2-4ac=(-4)^2-4(1)(5)=16-20=-4
which means the equation has two imaginary soultions
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I needa see it tho for I could help
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