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2 years ago

Which of the following equations can represent the function graphed below? Select all the possible

Mathematics

1 answer:

11Alexandr11 [23.1K]2 years ago

3 0

Answer:i dont not

Step-by-step explanation:

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What is 166.15801966 rounded

Colt1911 [192]

166.19
166
166.158
those are just some of the options

7 0

3 years ago

Type to justify why the two larger triangles are congruent

dexar [7]

Answer:

Step-by-step explanation:

We are dealing with triangle DAB and CBA.

Angles DAB and CBA are right angles making the triangles right triangles.

Side AB is congruent to side BA. That is a leg of each of the two triangles.

Side DB is congruent to side CA. Tat is a leg of each triangle.

The triangles are congruent by HL.

4 0

3 years ago

If f(x)=6^3x-4 and g(x) = 2x+2 find (f-g)(x)

natima [27]

Answer:

5x+3

Explanation:

(f+g)(x)=f(x)+g(x)

=2x−6+3x+9=5x+3

Hope this helped

4 0

4 years ago

Eduardo thinks of a number between 1 and 20 that has exactly 5 factors. What number is he thinking of?

Pepsi [2]

16- 2,8,1,16,4 ... I think he Is thinking of the number 16

4 0

3 years ago

Read 2 more answers

The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the imprope

lesya692 [45]

(1) D

$L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt$

Integrate by parts, taking

$u = t \implies \mathrm du=\mathrm dt$

$\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}$

Then

$L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}$

(2) A

$L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}$

7 0

3 years ago