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DedPeter [7]
3 years ago
7

Which expression is equivalent to (x^6y^8)^3/x^2y^2?

Mathematics
2 answers:
mash [69]3 years ago
5 0

Answer:

the last option

Step-by-step explanation:

Masja [62]3 years ago
3 0
For this case we have the following expression:
   (x ^ 6y ^ 8) ^ 3 / x ^ 2y ^ 2
 Rewriting and for power properties we have:
   (x ^ 18y ^ 24) / x ^ 2y ^ 2
   (x ^ (18-2) y ^ (24-2))
   (x ^ 16y ^ 22)
 Answer:
 
The equivalent expression is given by:
   (x ^ 16y ^ 22)
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A wheel is shaped like a circle with a diameter of 35 cm. To the nearest
zhenek [66]

Answer:

C = 110 cm

Step-by-step explanation:

The circumference is given by

C = pi *d

C = 3.14 * d

C = 3.14 * 35

C =109.9

Rounding

C = 110 cm

3 0
4 years ago
Please I need help answering this question is due tomorrow
Lynna [10]

Not sure but I think its C.

3 0
3 years ago
There is a bag filled with 2 blue, 4 red and 3 green marbles.
Lyrx [107]

Answer:

.753

Step-by-step explanation:

Let Ps = probability both marbles are the same color.

Let Pd = probability both marbles are a different color.

Pd = 1 -Ps

Let Pb = probability both marbles are blue

Let Pr = probability both marbles are red.

Let Pg = probability both marbles are green

Pb= 2/9 * 1/9 = 2/81

Pr= 4/9 * 3/9 = 12/81

Pg=.3/9 * 2/9= 6/81

Ps = Pb + Pr +Pg= 20/81

Pd =1-Ps= 61/81 = .753

Is this correct?

7 0
3 years ago
Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining Bismuth-210 transforms i
Luden [163]

Answer:

Approximately 76.5 mg.

Step-by-step explanation:

Given,

The initial quantity of the Bismuth-210, P = 233 mg,

Also, the rate of decay per day, r = 13 %

Thus, the quantity of the Bismuth-210 after 8 days would be,

A=P(1-\frac{r}{100})^8

=233(1-\frac{13}{100})^8

=233(1-0.13)^8

=233(0.87)^8

=76.4733194697

\approx 76.5\text{ mg}

3 0
3 years ago
A square piece of fabric has an area of 16x^2+40x+25 square inches. The length of each side of the fabric is cx+d, where c and d
lozanna [386]
A=(cx+d)^2=c^2x^2+2cdx+d^2\\\\c^2x^2+2xcd+d^2=16x^2+40x+25\\\Downarrow\\c^2=16;\ 2cd=40;\ d^2=25\\\Downarrow\\c=\sqrt{16};\ cd=20;\ d=\sqrt{25}\\\Downarrow\\\boxed{c=4\ and\ d=5}\\\\The\ length\ of\ side:cx+d=\boxed{4x+5}\\\\The\ perimeter\ of\ the\ piece\ of\ fabric:4(4x+5)=\boxed{16x+20}\\\\For\ x=2:\\16\cdot2+20=32+20=\boxed{52}
4 0
3 years ago
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