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Neko [114]
3 years ago
14

Find the difference

B%205x%20-%204%29%20-%20%28%20%7B6x%7D%5E%7B2%7D%20%20-%208%29" id="TexFormula1" title="( - {3x}^{3} - {7x}^{2} + 5x - 4) - ( {6x}^{2} - 8)" alt="( - {3x}^{3} - {7x}^{2} + 5x - 4) - ( {6x}^{2} - 8)" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Llana [10]3 years ago
6 0

Answer:

Step-by-step explanation:

Download xlsx
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Write an equation for the parabola that satisfies
givi [52]

Answer:

Step-by-step explanation:

y = -3(x-3)^2 + 4

4 0
3 years ago
Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
3 years ago
Read 2 more answers
Choose the equation below that represents the line passing through the point -3, -1 with a slope of 4
andre [41]

Answer:

Y=4x-5

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
49 × 66 + 49 × 34 = 49 × ( ____+ _____)​
Mashutka [201]

Answer:

49×66+49×34 = 49× (66+34)

5 0
3 years ago
Read 2 more answers
Area of paralellogram with base 15cm and height12cm
azamat

Answer:

180 cm2

Area of a polyhedron:

15(=base)x12(=height)

=180cm2

btw parallelogram is a 2D pic how you can come out a ''base'' and ''height''? It should be called a polyhedron. Your question is weird.

If so, your ''area of parallelogram'' is 15cm2 since your question is hecking  weird.

Btw it's 15cm2 not 15

Please check ur question b4 u ask

7 0
3 years ago
Read 2 more answers
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