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Xelga [282]
3 years ago
7

Simplify −2xy + 3x − 2xy + 3x and can you explain the answer?

Mathematics
2 answers:
irina1246 [14]3 years ago
8 0

Answer:

 -4xy+6x

Step-by-step explanation:

Given : Expression =  -2xy+3x-2xy+3x

Simplifying the expression :

Step 1. Write the expression =   -2xy+3x-2xy+3x

Step 2.  Add the similar elements:  3x+3x=6x

          =  -2xy-2xy+6x

Step 3. Add the similar elements:  -2xy-2xy=-4xy

           = -4xy+6x

Therefore, -4xy+6x is the simplified form of  -2xy+3x-2xy+3x

Karolina [17]3 years ago
6 0
First you must combine like terms, the two terms I this expression are x, and xy. So by adding -2xy to -2xy you get -4xy. Next you must add 3x to 3x. This gives you the simplified expression -4xy+6x. Hope this helps!
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Which statement is true?​
love history [14]
<h2>Hello!</h2>

The answer is:

The second option,

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

<h2>Why?</h2>

Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}

The statement is false, the correct form of the statement (according to the property of roots) is:

\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}

<h2>Second option,</h2>

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

The statement is true, we can prove it by using the following properties of exponents:

(a^{b})^{c}=a^{bc}

\sqrt[n]{x^{m} }=x^{\frac{m}{n} }

We are given the expression:

(\sqrt[m]{x^{a} } )^{b}

So, applying the properties, we have:

(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }

Hence,

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

<h2>Third option,</h2>

a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}

The statement is false, the correct form of the statement (according to the property of roots) is:

a\sqrt[n]{x}+b\sqrt[n]{x}=(a+b)\sqrt[n]{x}

<h2>Fourth option,</h2>

\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=m\sqrt{xy}

The statement is false, the correct form of the statement (according to the property of roots) is:

\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }

Hence, the answer is, the statement that is true is the second statement:

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

Have a nice day!

6 0
3 years ago
Help me!! A water tank is 1/8 full. The tank is 3/4 full when 42 gallons of water is added to the tank. How much can the water t
chubhunter [2.5K]

Answer(s):

1.) 56 gallons

2.) 7 gallons

3.) 28 gallons

Step-by-step explanation:

<u><em>Q1: How much water can the tank hold?</em></u>

Based on the question, we know that 3/4 of the tank equals 42 gallons. Divide 42 by the numerator, 3.

42/3 = 14

Now, multiply 14 by the denominator, 4.

14 x 4 = 56.

<em><u>So, the tank can hold 56 gallons.</u></em> [If you'd like to double check this answer, take the fraction 42/56 and simplify it to get 3/4.

<u><em>Q2: How much water was originally in the tank?</em></u>

We know that the tank's maximum capacity is 56 gallons. So, if it was 1/8 originally full, multiply 56 by 1/8. [Remember that 56 as a fraction can be written as 56/1]

1/8(56/1) = 7

<u><em>This means that the tank was originally 7 gallons full.</em></u> [If you'd like to double check this answer, take the fraction 1/8 and multiply the numerator and denominator by 7. This gets you 7/56, or 7 gallons out of the total capacity, 56 gallons.]

<u><em>Q3: How much water is in the tank when it is 1/2 full?</em></u>

Earlier, we found out that the maximum capacity of the tank is 56 gallons. To find out how many gallons it holds when its half full, divide 56 by 2.

56/2 = 28

<em><u>So, when the tank is 1/2 full, it contains 28 gallons.</u></em> [If you want to double check this answer, take  the fraction 28/56 and simplify it. When you do, you get 1/2.]

5 0
3 years ago
Read 2 more answers
A number increased by two-thirds of the number is 35. What is the number?
kirza4 [7]
21 would be the answer hope this helps :)
5 0
3 years ago
Read 2 more answers
Simplify (6^5 over 7^3)^2
love history [14]

Answer:

6^10 over 7^6.

Step-by-step explanation:

(6^5 over 7^3)^2

= 6^(5*2) / 7^(3*2)

=  6^10 over 7^6.

7 0
4 years ago
approximate each irrational number to the nearest hundredth without using a calculator square root of 118 and 319​
Strike441 [17]

Answer:

\sqrt{118}\approx 10.86

\sqrt{319}\approx 17.86

Step-by-step explanation:

Consider the provided number.

We need to find the approximate value of \sqrt{118} to the nearest hundredth.

First find two perfect squares that the irrational number falls between.

100

118 is lying between 100 and 121, therefore the square root value of 118 will be somewhere between 10 and 11.

\sqrt{100}

10

118 is closer to 121 as compare to 100.

Therefore, \sqrt{118}\approx 10.86

Consider the number \sqrt{319}

First find two perfect squares that the irrational number falls between.

289

319 is lying between 289 and 324, therefore the square root value of 319 will be somewhere between 17 and 18.

\sqrt{289}

17

319 is closer to 324 as compare to 289.

Therefore, \sqrt{319}\approx 17.86

8 0
3 years ago
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