Answer:
-63/2
Step-by-step explanation:
6( -5 1/4)
= 6(-21/4)
= -63/2
4). x/5 =8
x = 40
5). 2x/3 = 12
2x = 36
x = 36/2 = 18
6). x + 26 =12
x = 12 - 26 = -14
7). 8x + 1 = -23
8x = -23 -1
8x = -24
x = -24/8 = -3
8). 2x + 5 =15
2x = 15 - 5
2x = 10
x = 10/2 = 5
9). 3x - 1 = -29
3x = -29 + 1
3x = -28
x = -28/3 Or 9.33
10). 8x - 12 = 53
8x = 53 + 12
8x = 65
x = 65/8 Or 8.12
11). 4x + 7 = 25
4x = 25 - 7
4x = 18
x =18/4 = 9/2 Or 4.5
Answer:
A) A[p(t)] = 36πt²
B) 7234.56 square units
Step-by-step explanation:
<u>Given functions</u>:

<u>Part A</u>
To find the area of the circle of spilled paint as a function of time, substitute the function p(t) into the given function A(p):
![\begin{aligned}A(p) & = \pi p^2\\\\ \implies A[p(t)] & = \pi [p(t)]^2\\& = \pi (6t)^2\\& = \pi 6^2 t^2\\& = 36\pi t^2\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7DA%28p%29%20%26%20%3D%20%5Cpi%20p%5E2%5C%5C%5C%5C%20%5Cimplies%20A%5Bp%28t%29%5D%20%26%20%3D%20%5Cpi%20%5Bp%28t%29%5D%5E2%5C%5C%26%20%3D%20%5Cpi%20%286t%29%5E2%5C%5C%26%20%3D%20%5Cpi%206%5E2%20t%5E2%5C%5C%26%20%3D%2036%5Cpi%20t%5E2%5Cend%7Baligned%7D)
<u>Part B</u>
Given
Substitute the given values into the equation for A[p(t)} found in part A:
![\begin{aligned}A[p(8)] & = 36\pi t^2\\& = 36 \cdot 3.14 \cdot 8^2\\& = 36 \cdot 3.14 \cdot 64\\& = 113.04 \cdot 64\\& = 7234.56\:\: \sf square\:units\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7DA%5Bp%288%29%5D%20%26%20%3D%2036%5Cpi%20t%5E2%5C%5C%26%20%3D%2036%20%5Ccdot%203.14%20%5Ccdot%208%5E2%5C%5C%26%20%3D%2036%20%5Ccdot%203.14%20%5Ccdot%2064%5C%5C%26%20%3D%20113.04%20%5Ccdot%2064%5C%5C%26%20%3D%207234.56%5C%3A%5C%3A%20%5Csf%20square%5C%3Aunits%5Cend%7Baligned%7D)
Therefore, the area of spilled paint after 8 minutes if 7234.56 square units.
Answer:
A dilation is a transformation that changes the size of a figure. The original figure and translated figure seem to be (similar) I'm not sure about this I just researched it. Sorry:)))
Step-by-step explanation:
Answer:
sides are of 16 in
Step-by-step explanation:
here's your solution
==> area of square = 256 in^2. [given]
==> side of square = 4x
==> area of square= side^2
==> 4x^2 = 256
==> 16x^2 = 256
==> x^2 = 256/16
==> x^2 = 16
==> x = √16
==> x = 4
==> x = 4
hence sides are of 16 in
Hope it helps