<em>Given, 9−7x=5−3x</em>
<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.</em>
<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x</em>
<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x</em>
<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x⇒x= </em><em>4</em><em>/</em><em>4</em><em> </em><em> =1</em>
<em> =1Hence, required solution is x=1.</em>
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Answer:
49
Step-by-step explanation:
First you must do x times 6, x is really just 1. After you do that, you times it by 7.
Answer:
option b
Step-by-step explanation:
x = -3 (Not possible)
x = 5
So, x = 5
Answer: 3
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
1. Find the prime factorization of 27:
or 
2. The index of the radical is 3, therefore, you have rewrite it as following:
![\sqrt[3]{27}=\sqrt[3]{3^{3}}=3^{\frac{3}{3}}=3^{1}=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%5Csqrt%5B3%5D%7B3%5E%7B3%7D%7D%3D3%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D%3D3%5E%7B1%7D%3D3)
3. Therefore, as you can see, the answer is 3.
5 bc it’s multiplied by x
