All categories

3 years ago

The perimeter of a rectangle is 120 inches. The length is 10 more than the width. Find the length and width

Mathematics

1 answer:

OLga [1]3 years ago

4 0

The formula of a perimeter of a rectangle:

$P=2(l+w)$

We have:

$P=120\ in\\\\l=w+10$

Substitute

$2(w+10+w)=120\\\\2(2w+10)=120\ \ \ \ |:2\\\\2w+10=60\ \ \ \ |-10\\\\2w=50\ \ \ \ |:2\\\\w=25\\\\l=25+10=35$

<h3>Answer: Length = 35 in, Width = 25 in.</h3>

You might be interested in

Simplify (2x^2+6x+5) - (6x^2+3x+5)

Sati [7]

Your answer will turn out to be −4x^2+3x.

4 0

3 years ago

Read 2 more answers

The area is no more than 40 square feet. Write and solve an inequality that represents the value of x

Anna35 [415]

Answer:

well its a triangle so

40 divide by 20 is 2

but you have to mutiply that 2 by 2

Step-by-step explanation:

3 0

2 years ago

What is the simplified form of

umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4$

Step-by-step explanation:

Given the expression

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)$

solving the expression

$=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)$

apply the rule: $a^0=1,\:a\ne \:0$

$=-7+5x^2-x+6-\left(-8x^2+x+3\right)$

$=-7+5x^2-x+6+8x^2-x-3$

simplify

$=13x^2-2x-4$

Therefore, the simplified form is:

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4$

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

8 0

3 years ago

Mini muffins cost $3 per dozen

snow_tiger [21]

Answer:

agree with both because 1 dollar = 4 muffins so 2 x 4 = 8 muffins and 4x4 = 16 muffins

3 0

3 years ago

Subtract the quotient of h and 3,from 4 multiplied by 4.

zimovet [89]

4(3h-4)
12h-16?

I don't think that is right, I was kinda guessing

7 0

3 years ago