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4 years ago

How do you write 133x99?

Mathematics

1 answer:

swat324 years ago

8 0

133 x 99 = 13167
100% correct

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How many groups of 3/4 are in each of the following quantities?

____ [38]

Answer:

0.37

Step-by-step explanation:

6 0

3 years ago

Given function f(x)=x^2+5, determine the value of f(f(5))

zalisa [80]

Answer:

905

Step-by-step explanation:

So your original equation is f(x) = x² + 5

First lets work with the stuff inside the parentheses.

f(5) = 5² + 5 = 30

So now you are finding,

f(f(5)) => f(30)

f(30) = 30² + 5 = 900 + 5 = 905

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4 years ago

7x10^7 in standard form

Nikolay [14]

70000000 the reason that this is the answer to this is because if multiply 10 by 7 you will have 70 and just add 6 zeros

4 0

3 years ago

Work out:<br>6(10 - 23) + 20

barxatty [35]

Answer:

-58

Step-by-step explanation:

6 (10 - 23) + 20

=6 x (10 - 23) + 20

= 6 x (- 13) + 20

= -78 + 20

= -58

7 0

3 years ago

Demand for your tie-dyed T-shirts is given by the formula q = 510 − 90p0.5 where q is the number of T-shirts you can sell each m

telo118 [61]

Answer:

The demand will drop approximately 23 T-shirt per month.

Step-by-step explanation:

Consider the provided formula.

$q = 510-90p^{0.5}$

You currently sell T-shirts for $15 each and you raise your price by $2 per month,

That means p=$15 and $\frac{dp}{dt}=2$

We need to find how fast demand will drop.

So differentiate the above function with respect to time.

$\frac{dq}{dt} =0-45p^{0.5-1}\frac{dp}{dt}$

$\frac{dq}{dt} =-45p^{-0.5}\frac{dp}{dt}$

Substitute the respective values as shown:

$\frac{dq}{dt} =-45(15)^{-0.5}(2)$

$\frac{dq}{dt} \approx-23.24$

Hence, the demand will drop approximately 23 T-shirt per month.

3 0

4 years ago