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Pachacha [2.7K]
3 years ago
7

A family has two cars. the first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of

35 miles per gallon of gas. during one particular week, the two cars went a combined total of 1700 miles, for a total gas consumption of 60 gallons. how many gallons were consumed by each of the two cars that week?
Mathematics
1 answer:
Liula [17]3 years ago
8 0
The first car needed 56.7 gallons
the second car needed 24.3 gallons
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Gemiola [76]

Answer:

(a) <em>H</em>₀: <em>μ ≥ 5.70 </em><em>vs. </em><em>Hₐ</em>:<em>μ < 5.70</em>

(b) The rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).

(c) The value of the test statistic is -4.33.

(d) The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

Step-by-step explanation:

A hypothesis test should be conducted to determine that the if the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(a)

The hypothesis is:

<em>H</em>₀: The true mean breaking strength of the new bonding adhesive is not less than 5.70 Mpa, i.e. <em>μ ≥ 5.70</em><em>.</em>

<em>Hₐ</em>: The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa, i.e. <em>μ < 5.70</em><em>.</em>

(b)

The alternate hypothesis indicates that the hypothesis test is left-tailed.

The rejection region for the left tailed test will be towards the lower tail of the t<em>-</em>distribution curve.

The significance level of the test is: <em>α</em> = 0.01.

The critical value is:

t_{\alpha ,(n-1)}=t_{0.01,(10-1)}=t_{0.01,9}

Use the <em>t-</em>table for the critical value.

t_{\alpha ,(n-1)}=t_{0.01,9}=-2.821

Since rejection region is in the lower tail the critical value will be negative.

Thus, the rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).

(c)

The test statistic value is:

t=\frac{\bar x-\mu}{s/\sqrt{n}}

Given:

\bar x=5.07\\s=0.46\\n=10\\\mu=5.70

Compute the value of the <em>t</em>-statistic as follows:

t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{5.07-5.70}{0.46/\sqrt{10}} =-4.33

The value of the test statistic is -4.33.

(d)

The value of the test is less than the critical value.

t=-4.33

This implies that the test statistic lies in the rejection region.

Hence the null hypothesis will be rejected at 1% significance level.

<u>Conclusion:</u>

As the null hypothesis is rejected it can be concluded that the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(e)

The conditions required for the <em>t-</em>test for single mean to be valid is:

  • The data should be continuous.
  • The parent population should be normally distributed.
  • The sample should be randomly selected.

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Answer

The correct answer is B

Step-by-step explanation:

It is B because squares don't intersect so it cant be a

They are always congruent and equal so not c or d it has to be B

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Mr. Altamirano opens an account with a simple interest on an account with $1000 at 3% annually for 9 months. How much interest d
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Answer:

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Help please
Leno4ka [110]
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Part A
h x 10 + 60 x .25 = 115

Part B
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h = 10 (divided 10 into each side)

Part C
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Answer:

X=14

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Step-by-step explanation:

14-11=3

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