Answer:
Step-by-step explanation:
Let 
![m=(y^3)^{\frac{1}{2}}\\\\m=y^{3\times \frac{1}{2}}\ \ \ \ \ \ \ \ \ [as\ (x^a)^b=x^{ab}]\\\\m=y^{\frac{3}{2}](https://tex.z-dn.net/?f=m%3D%28y%5E3%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cm%3Dy%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%7D%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5Bas%5C%20%28x%5Ea%29%5Eb%3Dx%5E%7Bab%7D%5D%5C%5C%5C%5Cm%3Dy%5E%7B%5Cfrac%7B3%7D%7B2%7D)
Answer:
4(x - 9)^2 - 17
Step-by-step explanation:
A horizontal shift to the right by 9 changes x^2 to (x - 9)^2.
A vertical shift down by 1 changes - 16 to -17.
Therefore, the new equation is:
4(x - 9)^2 - 17
M=FD^2/(-Gn)
here is the solution
Answer:
- 1) y = 13.5x + 1
- 2) y = 12x + 4
- 3) Sam won the race
Step-by-step explanation:
<h3>Part 1</h3>
Sam's car is 1 ft in front of the start line and its speed is 13.5 ft/s.
<u>The distance after x seconds is:</u>
<h3>Part 2</h3>
Alice's car the speed 12 ft/s and after 3 seconds is 40 ft in front of the start line.
<u>The distance after x seconds is:</u>
- y = 12(x - 3) + 40 = 12x - 36 + 40 = 12x + 4
<h3>Part 3</h3>
<u>After 15 seconds the distance from the start line is:</u>
- Sam ⇒ y = 13.5*15 + 1 = 203.5 ft
- Alice ⇒ y = 12*15 + 4 = 184 ft
As we see Sam is further from the start line than Alice
