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solong [7]
3 years ago
9

Explain in your own words what domain and range mean

Mathematics
2 answers:
a_sh-v [17]3 years ago
3 0
A domain is an input that you put in an equation(x). A range is an output (y) that is the result of a certain input.

Hope this helps and please mark as brainliest!
tamaranim1 [39]3 years ago
3 0
Domain means the whole set of possible values of the variable on its own. 
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Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 117 mg/dl and
TiliK225 [7]

Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 117, \sigma = 10.6, n = 6, s = \frac{10.6}{\sqrt{6}} = 4.33

What is the level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L ?

This is the value of X when Z has a pvalue of 1-0.01 = 0.99. So X when Z = 2.33.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

2.33 = \frac{X - 117}{4.33}

X - 117 = 2.33*4.33

X = 127.1

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

6 0
3 years ago
ASAP<br><br> What is the value of x?
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3x-52=2x+2 (v.o.a)
3x-2x=2+52
x=54
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3 years ago
There are 12 boys in a math class. The total number of students s depends on the number of girls in the class g. write an equati
Pani-rosa [81]
12 + g = s
12 boys + g girls = s students
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3 years ago
Alberto is painting a large triangle on one wall of his bedroom. The base of the triangle is 4 ft, and the height is 8 ft. It ta
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Answer:   3.2 qts

Step-by-step explanation:

A=1/2 * b *h

1/2 * 4*8 = 16 square foot

Area is 16 square foot

Multiply the area by the quarts of paint it takes to cover 1 square foot.

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The least common multiple of 9 and 42 through prime factorization?
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Answer:

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