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4 years ago

Photo above please answer

Mathematics

1 answer:

alina1380 [7]4 years ago

5 0

I THINK the answer would be around 2/3/4 paper clips, I'm not sure. And keep in mind, I;m not responsible for any wrong answers/ invalid responses.

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A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med

Troyanec [42]

The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test - No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is $\frac{0.0396}{0.0396+0.0096}= \frac{33}{41}$

The probability of someone picked at random has cancer given that test result indicates no cancer is $\frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}$

7 0

3 years ago

At what point does y = 3x -2 intercept :

bezimeni [28]

Y axis= -2
x axis= 2/3

5 0

3 years ago

The scatter plot shows the number of absences in a week for classes of different sizes. Trevor concluded that there is a positiv

QveST [7]

This is right the answer is A.

8 0

3 years ago

Find the product. a^4(3a ^2 - 2a + 1)

Vikki [24]

a⁴(3a² - 2a + 1)

We just have to multiply each term inside the parentheses by a⁴ .

 a⁴(3a² ) = 3a⁶

 a⁴( - 2a ) = -2a⁵

 a⁴( 1) = a⁴

Now, just addum up : 3a⁶ - 2a⁵ + a⁴

7 0

3 years ago

Use the discriminate to determine the number and the nature of the solutions of the giving equation.

PolarNik [594]

Answer:

Since b^2 -4ac = 256 we have 2 real distinct root roots

Step-by-step explanation:

4x^2+12x=7

We need to subtract 7 to get it in the proper form

4x^2+12x-7=7-7

4x^2+12x-7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =4 b=12 and c=-7

(12)^2 - 4(4)(-7)

144 +112

256

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = 256 we have 2 real distinct root roots

7 0

3 years ago