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aleksley [76]
3 years ago
8

Which function has zeros of -8,1, and 3

Mathematics
1 answer:
grin007 [14]3 years ago
4 0

Answer:

A

Step-by-step explanation:

The zeros of a polynomial function are found by factoring in the form

a(x - r1)(x - r2)(x - r3) ... = 0, where each 'r-something' is a root (or solution) and 'a' is the leading coefficient.

Like if we have 3x² - 3x - 6 = 0

Factoring it as 3(x-2)(x + 1) = 0 shows the roots are 2 and -1.

And sine the right side is zero, we can even drop the factor of 3 on the left, and still have an equivalent equation (has same answers).

(x-2)(x + 1) = 0

The reason this works is because each factor in parentheses adds up to zero, creating a factor of zero in what is being multiplied on the left. And we know that if you have a series of factors in a product, and any one of those factors is zero, the whole product must be zero. So what is on the left equals the zero on the right, making the equation true.

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Answer: \frac{x-4}{2x-2}

Step-by-step explanation:

\frac{2x^2+5x+3}{x^2-3x-4} divided by \frac{4x^2+2x-6}{x^2-8x+16} is the same thing as multiplying \frac{2x^2+5x+3}{x^2-3x-4} by \frac{x^2-8x+16}{4x^2+2x-6}.

The equation we get is:

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With this equation, we can factor each equation:

\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}

We can cancel out like terms since they would be dividing each other:

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8 0
3 years ago
What is the value of the fourth term in the geometric sequence
ivanzaharov [21]

Answer:

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Step-by-step explanation:

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Thus, the geometric sequence formula specific to this case is

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a(4) = 15/4.

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