Question

Which function has zeros of -8,1, and 3

Answer 1

Answer:

A

Step-by-step explanation:

The zeros of a polynomial function are found by factoring in the form

a(x - r1)(x - r2)(x - r3) ... = 0, where each 'r-something' is a root (or solution) and 'a' is the leading coefficient.

Like if we have 3x² - 3x - 6 = 0

Factoring it as 3(x-2)(x + 1) = 0 shows the roots are 2 and -1.

And sine the right side is zero, we can even drop the factor of 3 on the left, and still have an equivalent equation (has same answers).

(x-2)(x + 1) = 0

The reason this works is because each factor in parentheses adds up to zero, creating a factor of zero in what is being multiplied on the left. And we know that if you have a series of factors in a product, and any one of those factors is zero, the whole product must be zero. So what is on the left equals the zero on the right, making the equation true.